The 1000 cubic centimeters of aluminium is enough for aluminium a trophy that will be in the shape of a right square pyramid and has a base edge of 10 cm and a slant height of 13 cm.
Step-by-step explanation:
The given is,
Volume of aluminium available is 1000 cubic centimeters
Shape of trophy is right square pyramid
Trophy has a base edge of 10 cm and slant height of 13 cm
Step:1
Formula for volume of right square pyramid,
.....................................(1)
Where, a - Base edge value
h - Height of pyramid
From given,
a = 10 cm
h = 13 cm
Equation (1) becomes,
Volume of trophy = 433.33 cubic centimeters
Compare with the volume of available aluminium and volume of right square pyramid,
So, the given volume of aluminium is enough to make right square pyramid shaped trophy.
Result:
The 1000 cubic centimeters of aluminium is enough for aluminium a trophy that will be in the shape of a right square pyramid and has a base edge of 10 cm and a slant height of 13 cm.
Answer:
d
Step-by-step explanation:
12
<em><u>To </u></em><em><u>find:</u></em>
<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>The</u></em><em><u> </u></em><em><u>value</u></em><em><u> of</u></em><em><u> </u></em><em><u>x</u></em>
<em><u>=</u></em><em><u>></u></em>
<em><u>
</u></em>
<em><u>Now,</u></em><em><u> we'll</u></em><em><u> </u></em><em><u>move </u></em><em><u>-</u></em><em><u>8</u></em><em><u> </u></em><em><u>to </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>side </u></em><em><u>i.e </u></em><em><u>the </u></em><em><u>RHS </u></em><em><u>side,</u></em>
<em><u>which</u></em><em><u> </u></em><em><u>results</u></em><em><u> </u></em><em><u>in </u></em><em><u>the </u></em><em><u>change</u></em><em><u> </u></em><em><u>of </u></em><em><u>it's</u></em><em><u> </u></em><em><u>sign(</u></em><em><u>-</u></em><em><u> </u></em><em><u>converts</u></em><em><u> </u></em><em><u>into </u></em><em><u>+</u></em><em><u>)</u></em>
<em><u>=</u></em><em><u>></u></em>
<em><u>
</u></em>
<em><u>Now </u></em><em><u>,</u></em><em><u> we'll</u></em><em><u> </u></em><em><u>add </u></em><em><u>the </u></em><em><u>Numbers</u></em>
<em><u>=</u></em><em><u>></u></em>
<em><u>
</u></em>
<h2><em><u>Hence</u></em><em><u>,</u></em><em><u>-</u></em><em><u>3</u></em><em><u> </u></em><em><u>is </u></em><em><u>the</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>answer</u></em><em><u>.</u></em></h2>
<em><u>^</u></em><em><u>-</u></em><em><u>^</u></em>
I think that translation is the only one that DOES preserve orientation.
Rotation and reflection definitely don't, and I'm not sure about dilation.
