NaHCO3(s) + HCl(aq) — NaCl(s) + H2011) + CO2

Which of the following best describes the way that scientists make observations

ahrayia [7]

Answer: D. Use tools to help improve their senses when they make observations.

Observation is the outcome of a scientific procedure, which is followed to answer the questions related to a scientific inquiry. In order to make observation scientists need to use tools that can help in improving their senses like visual, sensation and hearing aids, so as to make observation accurate, and conclusive in a research.

3 0

3 years ago

What is the weight of a 30.0 kg object? 3.0 N 300 N 6.8 N 132 N

andreyandreev [35.5K]

Explanation:

$w \: = mg \\ = 30\:kg \times 10\:ms^{-2}\\=300\:kg\:ms^{-2} \\ = 300\:N$

6 0

3 years ago

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25.0cm3 of s saturated potassium hydroxide is neutralized by 35.0cm3 of hydrogen chloride acid of concentration 0.75 mol/dm3. Ca

Kamila [148]

Answer:

Concentration of the original $\rm KOH$ solution: approximately $1.05\; \rm mol \cdot dm^{-3}$ .

Explanation:

Notice that the concentration of the $\rm HCl$ solution is in the unit $\rm mol\cdot dm^{-3}$ . However, the unit of the two volumes is $\rm cm^{3}$ . Convert the unit of the two volumes to $\rm dm^{3}$ to match the unit of concentration.

$\begin{aligned} V(\mathrm{NaOH}) &= 25.0\; \rm cm^{3} \\ &= 25.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0250\; \rm dm^{3} \end{aligned}$ .

$\begin{aligned} V(\mathrm{HCl}) &= 35.0\; \rm cm^{3} \\ &= 35.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0350\; \rm dm^{3} \end{aligned}$ .

Calculate the number of moles of $\rm HCl$ molecules in that $0.0350\; \rm dm^{3}$ of $0.75\; \rm mol \cdot dm^{3}$ $\rm HCl\!$ solution:

$\begin{aligned}n(\mathrm{HCl}) &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.00350\; \rm dm^{3} \times 0.75\; \rm mol \cdot dm^{3} \\ &\approx 0.02625\; \rm mol\end{aligned}$ .

$\rm HCl$ is a monoprotic acid. In other words, each $\rm HCl\!$ would release up to one proton $\rm H^{+}$ .

On the other hand, $\rm KOH$ is a monoprotic base. Each $\rm KOH\!$ formula unit would react with up to one $\rm H^{+}$ .

Hence, $\rm HCl$ molecules and $\rm KOH\!$ formula units would react at a one-to-one ratio.

${\rm HCl}\, (aq) + {\rm NaOH}\, (aq) \to {\rm NaCl}\, (aq) + {\rm H_2O}\, (l)$ .

Therefore, that $0.02625\; \rm mol$ of $\rm HCl$ molecules would neutralize exactly the same number of $\rm NaOH$ formula units. That is: $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ .

Calculate the concentration of a $\rm NaOH$ solution where $V(\mathrm{NaOH}) = 0.0250\; \rm dm^{3}$ and $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ :

$\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} \\ &= \frac{0.02625\; \rm mol}{0.0250\; \rm dm^{3}}\approx 1.05\; \rm mol \cdot dm^{-3}\end{aligned}$ .

7 0

3 years ago

Which type of molecule is shown below? O A. Alkane B. Alkyne C. Aromatic D. Alkene

V125BC [204]

Answer:

alkyne molecules is shown

3 0

3 years ago

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In a single carbon bond, two carbon atoms share pair of electrons.

torisob [31]

Answer:

C-C

A carbon has 4 valence electrons meaning it can share 4 electrons and is in short of 4 electrons to fill it outer energy shell making it 8. Which results to 2 double covalent bonds ,meaning there was a sharing of 2(4) = 8 electrons . Hope this helps . Your statement above is true .

8 0

3 years ago