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fomenos
3 years ago
15

Urgent‼️‼️‼️‼️‼️‼️ Find the average atomic mass of element Uus. 284Uus 283.4 amu 34.60 % 284.7 amu 21.20 % Uus 287.8 amu 44.20 %

285Uus 288​

Chemistry
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

285.6

Explanation:

(283.4×0.3460)+(284.7×0.2120)+(287.8×0.4420)

=285.6204

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Acetylsalicylic acid (C9H8O4) is a monoprotic acid commonly known as aspirin. A typical aspirin tablet, however, contains only a
pashok25 [27]

Answer:

6 grains

Explanation:

The equation of the reaction between NaOH and aspirin is;

C9H8O4(aq) + NaOH (aq) ------>C9H7O4Na(aq) + H2O(l)

Amount of NaOH reacted = concentration × volume = 0.1466 M × 14.40/1000 L = 2.11 × 10^-3 moles

Given that aspirin and NaOH react in a mole ratio of 1:1 from the balanced reaction equation above, the number of moles of aspirin reacted is 2.11 × 10^-3 moles

Hence mass of aspirin reacted = 2.11 × 10^-3 moles × 180.2 g/mol = 0.38 g

If 1 grain = 0.0648 g

x grains = 0.38 g

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3 years ago
What two motions combine to produce orbit?
Alex73 [517]
<span>Forward & falling. Hope this helps!</span>
6 0
3 years ago
How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
What is the chemical formula for 8.6 mol of sulfur and 3.42 mol of phosphorus
adell [148]

The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅

<h3>How do I determine the formula of the compound?</h3>

From the question given above, the following data were obatined:

  • Sulphur (S) = 8.6 moles
  • Phosphorus (P) = 3.42 mole
  • Chemical formula =?

The chemical formula of the compound can be obtained as follow:

Divide by their molar mass

S = 8.6 / 32 = 0.26875

P = 3.42 / 31 = 0.11032

Divide by the smallest

S = 0.26875 / 0.11032 = 2.44

P = 0.11032 / 0.11032 = 1

Multiply by 2 to express in whole number

S = 2.44 × 2 = 5

P = 1 × 2 = 2

Thus, the chemical formula is P₂S₅

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3 years ago
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