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dybincka [34]
3 years ago
15

Is it possible to identify something as an element, compound or pure substance

Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0
Yes it is possible.
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Which type of clouds are feathery,high in the sky,and are made mostly of ice crystals?
Temka [501]
The cloud with those characteristics is #1
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3 years ago
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A gas mixture contains 0.700 mol of N2, 0.300 mol of H2, and 0.400 mol of CH4. Calculate the pressure of the gas mixture and the
Nitella [24]

Answer:

Pressure of the gas mixture: 4.30 atm

Partial pressure N₂ = 2.15 atm

Partial pressure H₂ =  0.91 atm

Partial pressure CH₄ = 1.23 atm

Explanation:

To determine partial pressure we sum the total moles in order to find out the total pressure

We can work with mole fraction

We apply the Ideal Gases Law

0.700 N₂ + 0.300 H₂ + 0.400 CH₄ = 1.4 moles

We replace data  → P . V = n . R .T

T° must be at K →  27  °C + 273 = 300 K

P . 8 L = 1.4 mol . 0.082 L.atm/mol.K  . 300 K

P = ( 1.4 mol . 0.082 L.atm/mol.K  . 300 K) / 8 L = 4.30 atm (Total pressure)

We apply the mol the fraction for the partial pressure

Moles x gas / total moles = partial pressure x gas / total pressure

Mole fraction N₂ → 0.700 /1.4 = 0.5

Partial pressure N₂ = 0.5 . 4.30 atm =2.15 atm

Mole fraction H₂  →  0.300 / 1.4 = 0.21

Partial pressure H₂ = 0.21 . 4.30 atm = 0.91 atm

Mole fraction CH₄ → 0.400 /1.4 = 0.28

Partial pressure CH₄ = 0.28 . 4.30 atm =1.23 atm

7 0
3 years ago
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Why is acid added to water during eletrolysis
DedPeter [7]

Answer:

Pure water is a non conductor of electricity and dilute acids in their aqueous solutions form free ions, which conducts electricity. Thus when we need to electrolyse water, a dilute acid is added to increase its conductivity.

4 0
2 years ago
using the knowledge of the structures of argon and chlorine. Explain why they are both gases at room temperature ?
aleksley [76]
Because at atmospheric pressure the boiling point is below room temperature, just like Oxygen, Nitrogen etc
3 0
3 years ago
What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm?
AlekseyPX

The   new volume of a 250  Ml   sample of gas at 300k  and  1atm  if  heated to 350 k  at  1 atm  is  291.67  Ml



<u>calculation</u>

This  is  solved  using  the  Charles  law formula  since the  pressure  is constant.

that is V1/T1 = V2/T2  where,

V1 =250 ml

T1=300  K

V2=?

T2= 350 k


by making V2 the subject   of  the formula  by  multiplying  both side by T2

V2= T2V1/T1

V2= (350 K x 250 ml) / 300K =291.67 Ml


5 0
3 years ago
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