Find the zeros of the function p(x) = -9x^2 + 1
1 answer:
Answer:
Zeros: 1/3 and -1/3
Step-by-step explanation:
You can solve this for the zeros by using the factoring method:
p(x) = (-3x-1)(3x-1)
Then, you take each factored equation and set it equal to zero:
-3x-1=0
3x-1=0
Then, solve for zero:
-3x=1 x=-1/3
3x=1 x=1/3
Your zeros are 1/3 and -1/3.
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