If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
To do this problem you use is/of=percent/100
So:
320/750=x/100
cross multiply
32,000=750x
divide both sides by 750
x=42.66 repeating
ANSWER: X=42.66 REPEATING
There are 4 vertices of a square to the right.
Using the slope-intercept form, y=mx + b to find the slope I found that correct answer is 2/5.
Get them to have a common denominator so you can add them
(1/3)×2= 2/6 and (1/2)×3= 3/6
Add them together
(2/6)+ (3/6)= 5/6
So 5/6 of the class planted either marigolds or tulips and 1/6 of the class planted neither
