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LuckyWell [14K]
2 years ago
7

Help help help math math

Mathematics
2 answers:
VashaNatasha [74]2 years ago
8 0
2|x-3|=30
|x-3|=15
x-3=-15
x-3=15
x=-12
x=18
Contact [7]2 years ago
4 0

\frac{2 |x - 3| }{5}  = 6 \\

5 \times  \frac{2 |x - 3| }{5}  = 5 \times 6 \\

2 |x - 3|  = 30

\frac{2 |x - 3| }{2}  =  \frac{30}{2}  \\

|x - 3|  = 15

x - 3 = 15

x - 3 + 3 = 15 + 3

x = 18

<h2>OR</h2>

x - 3 =  - 15

x - 3 + 3 =  - 15 + 3

x =  - 12

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A hockey team plays in an arena with a seating capacity of 15,000 spectators. With the ticket price set at , average attendance
Goshia [24]

Answer:

Ticket price 11,5 $  

R(max)  =  132750 $

Step-by-step explanation:INCOMPLETE QUESTION

The ticket price is missing

We will assume 12 $

Let call x the decreasing number of the ticket price

The revenue is

R =  ticket price * numbers of spectator

R(x) =  (  12 - x ) *  ( 11000 + 1000*x )   for all   0 ≤ x  ≤ 4   ( the seating capacity is 15000 )

R(x) =  132000 + 12000*x  - 11000*x - 1000*x²

R(x) =  132000 + 1000*x  - 1000*x²

Taking derivatives on both sides of the equatio we get:

R´(x)  =  1000  -  2000x

R´(x)  = 0    ⇒    1000  -  2000x  =  0

x  =  1000/2000    ⇒  x = 0,5 $

We notice that R´´(x)  < 0    then we have a maximum for  x = 0,5

and the price is 12 - 0,5  = 11,5 $ for ticket

and the R(max) is

R(max) = 132000 + 1000*0,5  + 1000* (0,5)²

R(max) = 132000 + 500 + 250

R(max) = 132750 $

7 0
3 years ago
A principal of $4,570 is placed in an account that earns 4. 5% interest. If the interest is compounded annually, how much money
iVinArrow [24]

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8 0
2 years ago
He temperature at noon at a ski resort is 3°F. The temperature drops 8°F by midnight.
Norma-Jean [14]

Answer:

thye answer is -5f

Step-by-step explanation

5 0
3 years ago
ANSWERR ASAPP!!! I GIVE BRAINLIESTT!!<br><br>Answer b and correct c and a if wrong ​
FrozenT [24]

Answer:

b is (4,55). c is correct I believe.

Step-by-step explanation:

You need to find where the lines cross on the graph. You see that at point (4,55)

6 0
3 years ago
Read 2 more answers
The polynomial $f(x)$ has degree 3. If $f(-1) = 15$, $f(0)= 0$, $f(1) = -5$, and $f(2) = 12$, then what are the $x$-intercepts o
Alex_Xolod [135]

Your calculator's cubic regression function can tell you the equation is

... f(x) = 2x³ + 5x² -12x = x(x +4)(2x-3)

The x-intercepts are -4, 0, +1.5.

_____

If you want to solve this "by hand", you can first of all recognize that since there is an x-intercept at 0, the cubic will only have three coefficients. That is, you can write the equation as

... f(x) = ax³ + bx² + cx

Substituting the given points (except (0, 0)) gives three linear equations in a, b, c.

... -a +b -c = 15 . . . . . for x=-1

... a + b + c = -5 . . . . for x=1

... 8a +4b +2c = 12 . . for x=2

adding the first two equations gives 2b=10, or b=5. Now, you can reduce the system to

... a + c = -10

... 4a +c = -4

Subtracting the first of these equations from the second gives 3a=6, or a=2. That tells you c=-12 (from a+c=10).

Then your equation is

... f(x) = x(2x² +5x -12)

Factoring by any of the usual techniques, or graphing, or using the quadratic formula will tell you the zeros (x-intercepts) are as above.

_____

Since the input values are sequential, you can also develop the function from differences of the output values. Those are 15, 0, -5, 12. First differences are -15, -5, +17. Second differences are +10, +22. The third difference is 12. Using the first of these differences in appropriate places in the interpolating polynomial formula, we have

... f(x) = 15 + (x+1)(-15 + (x)/2·(10 + (x-1)/3·(12))) = 2x³ +5x² -12x . . . . as above

4 0
3 years ago
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