Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be
Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
4.6 is the correct answer. Hope I helped:)
Answer:
(a)
Number of cars with defective turn signals = 65
Number of cars with no defective turn signals = 410 - 65 = 345
<u>Required probability:</u>
- P = 345/410*100% ≈ 84.15%
(b)
Number of cars with defects = 65 + 35 = 100
Number of cars with no defects = 410 - 100 = 310
<u>Required probability:</u>
- P = 310/410*100% ≈ 75.61%
Answer:
It would probably be 15 actually