For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}
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How to get the domain and range?</h3>
Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:
x - 7 ≥ 0.
Solving for x we get:
x ≥ 0 + 7
Then the domain is:
x ≥ 7
To get the range, we evaluate in the minimum of the domain:
f(7) = √(7 - 7) + 9 = 9
Then the range is the set of all values larger than 9, because the function is increasing.
So the range is R: y ≥ 9.
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Answer:
Not Similer
Step-by-step explanation:
we can use the process of elimination, first AA isn't it because the corresponding angles arn't equal, next SSS itsn't it because we don't know the side lengths, and lastly SAS isn't it because we still don't know the side lengths.
Answer:
2z-6
Step-by-step explanation:
2(z-3)
2(z)-2(3)=2z-6
C) 360
because they can all be multiplied to get 360
20 times 18 24 times 15 45 times 8
Answer:
(x-9)²+(y-5)²=64
Step-by-step explanation:
Centre is (9,5) and radius is 16*pi/2*pi=8. Plug it in the equation of circles
