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kaheart [24]
3 years ago
6

I give Brainliest!

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer: Equilateral triangles are also right triangles sometimes. All angles of an equilateral are congruet sometimes.

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“If a quadrilateral is a parallelogram, then it is a square”
yuradex [85]
Yes that is true, all opposite sides would be parallel, and all the corners are 90 degrees, then yes it is true
6 0
3 years ago
The water level of a river is 170 feet. The river recedes 4 feet each year. Ingrid claims that the equation that represents this
Vladimir [108]

Sample Answer: No, Ingrid is incorrect. The initial value in the scenario is 170 feet, which represents the y − intercept. Receding 4 feet in the scenario represents the rate of change, which is the slope. In slope-intercept form, y = mx + b, where m represents slope and b represents the y−intercept, so the correct equation is y = −4x + 170.


3 0
3 years ago
Read 2 more answers
Create and Solve an equation to find the unknown angle. ​
valentina_108 [34]

Answer:

Equation: 2x + 3x + 10 = 180

x = 34

Top angle = 68 degrees

Bottom angle = 112 degrees

Step-by-step explanation:

The two angles add to 180, so set them equal to 180.

2x + 3x + 10 = 180

5x + 10 = 180

     - 10    - 10

5x = 170

/ 5    / 5

x = 34

Plug x into angles,

2(34) = 68

3(34) + 10 = 112

8 0
3 years ago
Read 2 more answers
Find p (-5) p(3) for p(x)=2x^5-9x^4-2x^2+12x-2
Margarita [4]

Answer:

We have to evaluate the function p with the numbers on the argument of them, that is:

p(-5) = -11887

p(3)= -191

Step-by-step explanation:

First we are going to evaluate the functions and then to replace x by the corresponding number on the argument:

p(-5)= 2 (-5)^5 -9(-5)^4 -2(-5)^2+12(-5) +2 = -11887

p(3) =2(3)^5-9(3)^5-2(3)^2+12(3)-2 =-191

8 0
3 years ago
Train A travels 30 miles in 20 minutes at a constant speed. Train B travels 20 miles in 15 minutes at a constant speed. Redo Whi
krek1111 [17]
\begin{gathered} \text{Train A}\Rightarrow\frac{30\text{ miles}}{20\text{ minute}}=1.5\text{ miles/minute} \\ \text{ Train B}\Rightarrow\frac{20\text{ miles}}{15\text{ minute}}=1.34\text{ miles/minute} \\ \text{The train A is going faster.} \end{gathered}

3 0
1 year ago
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