3 years ago

Help me please someone

Mathematics

1 answer:

Gelneren [198K]3 years ago

7 0

What you need help with

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Find the equation of a line parallel to – 2y = –2 – 2x that passes through the<br> point (9,-9).

riadik2000 [5.3K]

Answer:

2y + 2x = 0

Step-by-step explanation:

First you have to find the slope of the line.

Parallel lines have same slope

2y = -2-2x

y=-1-1x, y=-1x-1

slope = -1

Use point slope formula

y-y=m(x-x)

y-(-9) = -1(x-9)

y+9 = -1(x-9)

y+9 = -1x+9

y = -x

y + x = 0

2y + 2x = 0

7 0

2 years ago

The radius of the aluminum (Al) atom is 143 pm. The radius of the aluminum ion (Al3+) is 54 pm. By what percentage did the radiu

Romashka [77]

Answer:

There was 62.23% change in radius as the ion formed.

Step-by-step explanation:

6 0

3 years ago

Help. I need to factor and solve using the quadratic formula <br>-x^2+2x=7

aleksandrvk [35]

Answer:

Irreducible factorization

Step-by-step explanation:

7 0

3 years ago

How do u factor this

PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

$p(x)=x^2+bx+c$

has roots $x_1,\ x_2$ , then you have the following factorization:

$p(x) = (x-x_1)(x-x_2)$

In order to find the roots, you can use the usual formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the first example, this formula leads to

$x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}$

So, you can factor

$x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})$

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

$f(1.5)=-5.25$

you get

$f(-1.5) = 1.5c-3 = -5.25$

Add 3 to both sides:

$1.5c = -2.25$

Divide both sides by 1.5:

$c = 1.5$

7 0

3 years ago

Tell whether each function is linear or nonlinear use the drop down menus to show yo answer

saveliy_v [14]

Answer:

If it's a straight line it's linear, if it curves it's non-linear.

Step-by-step explanation:

6 0

3 years ago