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3 years ago

Help me please someone

Mathematics

1 answer:

Gelneren [198K]3 years ago

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Marisa painted 1/2 of her bedroom in 3/4 of an hour. At this rate, how long would it take her to paint the entire room?

marishachu [46]

6/8 because she painted half of her room in 3/4 of an hour and add half of that and you get 6/8! Hope this helps! Im not very good at math so don't judge me if its wrong...

8 0

3 years ago

Read 2 more answers

Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).Find the midpoint of the line segment whose endpoi

jek_recluse [69]

Answer:

The midpoint is $(1,-2)$

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

$(x1,y1)=(-2,5)$

$(x2,y2)=(4,-9)$

substitute

$M(\frac{-2+4}{2},\frac{5-9}{2})$

$M(1,-2)$

8 0

2 years ago

During the past year, Zara and Ivan each read 2 books, but George read 7, Ali read 12, and Marsha read 25. The median number of

gogolik [260]

Answer:

D = 7

Step-by-step explanation:

To find the median, we must first list the amount of books each person read, and then put them in order.

2, 2, 7, 12, 25

These are already in order from smallest to greatest, which is awesome. We can then cross out one number from each side until we end up with either one or two numbers. We then find the average of those 1 or 2 numbers to find our median.

2, 3, 7, 12, 25

cross 2 and 25 out

3, 7, 12

cross 3 and 12 out

Our median is thus 7

7 0

2 years ago

Someone please help me with this

11Alexandr11 [23.1K]

2/3 and 8/12 are proportional but 3/14 and 8/28 aren’t

5 0

2 years ago

For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp

Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

$\frac{1}{365}$

a) Probability that exactly 3 people have same birthday = $\frac{1}{365^3}$

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = $\frac{1}{365^3}$

Expected value of days = np = $\frac{1}{365^2}$

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0

3 years ago