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Leto [7]
2 years ago
13

WILL GIVE BRAINLIEST!!! Solve 3(2x - 3) = 15. Explain ALL steps.

Mathematics
2 answers:
viva [34]2 years ago
7 0
3 x 2x = 6x
3 x -3 = -9

6x - 9 = 15
Add nine to both sides of the equal sign
15+9= 24

Divide both sides by 6

24/6= 4

X=4

Tell me if this helps
Please mark me as brainliest
butalik [34]2 years ago
6 0

Answer:

x=4

Step-by-step explanation:

distributive property goes first.

you get 6x-9=15

add 9 on both sides so 9 cancells out on the left side.

you get 6x=24

divide by 6 and you get x=4

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0.3r=2.1. whats the solution
vivado [14]
In order to find "r", you need to isolate it. So in order to isolate it, you do the inverse operation. In this case, it would be division because 0.3 is being multiplied by "r". So you divide by 0.3 on both sides to get 7. 
3 0
3 years ago
What is the answer to this question
umka21 [38]
First you bring the 9 over with the seven 
-2= \sqrt[3]{x+9}
Now cube both sides
-8=x+9
Finally subtract 9 over and get
x=-17


Check
7=9+ \sqrt[3]{-17+9}
7=9+ \sqrt[3]{-8}
7=9+(-2)
7=7

5 0
4 years ago
Find the slope of the line that passes through (-21, 59) and (35, -13).
ivann1987 [24]

Answer:

-1.29

Step-by-step explanation:

y2-y1÷x2-x1

-13-59÷-35--21

-72÷56

-1.29

4 0
3 years ago
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inysia [295]
Multiply all of them then that’s ur answer
6 0
3 years ago
Read 2 more answers
Find the coordinates of the point which divides the join of (-1,7) and (4.-3) in the ratio 2:3 ??
d1i1m1o1n [39]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h2>

Find the coordinates of the point which divides the join of (-1,7) and (4,-3) in the ratio 2:3 ?

<h2><u>Solution</u>:-</h2>

Let the given points be A(-1,7) and B(4,-3)

Now,

Let the point be P(x, y) which divides AB in the ratio 2:3

Here,

<h3>{ \bf  x \: = \frac{m_1 x_2 \: + \: m_1 x_1}{m_1 \: + \: m_2}}</h3>

Where,

m_1 = 2 , m_2 = 3

x_1 = -1 , x_2 = 4

\therefore Putting values we get,

x = \frac{2 \: × \: 4 \: + \: 3 \: × \: -1}{2 \: + \: 3}

x = \frac{8 \: - \: 3}{5}

x = \frac{5}{5}

x = 1

Now,

Finding y

<h3>{ \bf  y \: = \frac{m_1 y_2 \: + \: m_2 y_1}{m_1 \: + \: m_2}}</h3>

Where,

m_1 = 2 , m_2 = 3

x_1 = 7 , x_2 = -3

\therefore Putting values we get,

y = \frac{2 \: × \: -3 \: + \: 3 \: × \: 7}{2 \: + \: 3}

y = \frac{-6 \: + \: 21}{5}

y = \frac{15}{5}

y = 3

Hence x = 1, y = 3

So, the required point is P(x, y)

= P(1, 3)

<h3>The coordinates of the point is P(1, 3). [Answer]</h3>

_______________________________________

<u>N</u><u>o</u><u>t</u><u>e</u>:- Refer the attachment.

_______________________________________

5 0
3 years ago
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