In order to find "r", you need to isolate it. So in order to isolate it, you do the inverse operation. In this case, it would be division because 0.3 is being multiplied by "r". So you divide by 0.3 on both sides to get 7.
First you bring the 9 over with the seven
![-2= \sqrt[3]{x+9}](https://tex.z-dn.net/?f=-2%3D%20%5Csqrt%5B3%5D%7Bx%2B9%7D%20)
Now cube both sides

Finally subtract 9 over and get

Check
![7=9+ \sqrt[3]{-17+9}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-17%2B9%7D%20)
![7=9+ \sqrt[3]{-8}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-8%7D%20)

7=7
Answer:
-1.29
Step-by-step explanation:
y2-y1÷x2-x1
-13-59÷-35--21
-72÷56
-1.29
Multiply all of them then that’s ur answer
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h2>
Find the coordinates of the point which divides the join of (-1,7) and (4,-3) in the ratio 2:3 ?
<h2><u>Solution</u>:-</h2>
Let the given points be A(-1,7) and B(4,-3)
Now,
Let the point be P(x, y) which divides AB in the ratio 2:3
Here,
<h3>

</h3>
Where,
= 2 ,
= 3
= -1 ,
= 4
Putting values we get,
x = 
x = 
x = 
x = 1
Now,
Finding y
<h3>

</h3>
Where,
= 2 ,
= 3
= 7 ,
= -3
Putting values we get,
y = 
y = 
y = 
y = 3
Hence x = 1, y = 3
So, the required point is P(x, y)
= P(1, 3)
<h3>The coordinates of the point is P(1, 3). [Answer]</h3>
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<u>N</u><u>o</u><u>t</u><u>e</u>:- Refer the attachment.
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