8 bits make a byte or a character.
The answer to that would have to be c I think this is it so a feature bl bl bla
Answer:
Complete Python code with step by step comments for explanation are given below.
Python Code:
# creating a function named scrabble_number that will take num as input argument
def scrabble_number(num):
# print the original number
print("The original number is: ",num)
# we can implement the required logic by using python built-in functions join() and zip()
scrambled = ''.join([char[1]+char[0] for char in zip(num[::2], num[1::2])])
# print the scrambled number
print("The scrambled number is: " + str(scrambled))
Driver code:
scrabble_number('123456')
Output:
The original number is: 123456
The scrambled number is: 214365
Answer:
range
Explanation:
range(num1, num2) returns the numbers from num1 up to but not including num2.
Example: range(1, 4) will return the numbers 1, 2, 3.
Hope this helps :)