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Brilliant_brown [7]
3 years ago
14

A company is utilizing servers, data storage, data backup, and software development platforms over an Internet connection.

Computers and Technology
1 answer:
Anarel [89]3 years ago
8 0

Answer:

The answer is A. Cloud computing

Explanation:

Cloud computing is the process of using the internet to store, mange and process data rather than using a local server or a personal computer.

The term  cloud computing is generally used to describe data centers available to many users over the Internet.  

Therefore the company's approach to computing resources can be said to be cloud computing because it uses the internet  for data storage, data backup, and software development  

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D. enter because if you enter something on a cuputer or laptop your selecting something
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Mad libs are activities that have a person provide various words, which are then used to complete a short story in unexpected(an
Vsevolod [243]

did you just put random a*s word together and expect us to know the ¨answer¨

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3 years ago
You develop an app, and you don’t want anyone to resell it or modify it. This is an example of: A
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Answer:

C, proprietary software

Explanation:

Proprietary software, also known as non-free software, is computer software for which the software's publisher or another person reserves some rights from licensees to use, modify, share modifications, or share the software. It sometimes includes patent rights.

7 0
3 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
3 years ago
A computer is performing a binary search on the sorted list of 7 numbers below.
suter [353]

Answer:

The answer is "Option D".

Explanation:

Binary search is also an efficient mechanism for only a sorted item list. It separates the element into one half of the checklist repeatedly, till you have narrowed it down to the only single place.

In this search, the number of comparisons is much more efficient than in the series to use the binary search approach, the items also should be shown, that's why the last choice is correct.

6 0
3 years ago
Read 2 more answers
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