Respuesta:
199.5 g
Explicación:
Paso 1: Escribir la reacción balanceada
2 Al + 3 H₂SO₄ ⇒ Al₂(SO₄)₃ + 3 H₂
Paso 2: Calcular la masa pura de 50 g de Al
Aluminio tiene 10% de impurezas, es decir, 10% de 50 g = 5 g. Luego, tiene 50 g - 5 g = 45 g de Al puro.
Paso 3: Calcular la masa teórica de Al₂(SO₄)₃ obtenida a partir de 45 g de Al
La relación de masas de Al₂(SO₄)₃ a Al es 342:54.
45 g Al × 342 g Al₂(SO₄)₃/54 g Al = 285 g Al₂(SO₄)₃
Paso 4: Calcular la masa real de Al₂(SO₄)₃ obtenida
El rendimiento de la reacción es de 70%.
285 g × 70% = 199.5 g
Answer:
The answer to your question is 2 moles of Carbon
Explanation:
Carbon-12 means it has a molecular mass of 12g / mol. Mol is defined as the number of grams of an atom in one mol.
To solve this problem, we use proportions
12 g of Carbon ---------------- 1 mol of Carbon
24 g of Carbon -------------- x
x = ( 24 g x 1 mol ) / 12 g
x = 24 / 12
x = 2 mol of Carbon
Answer:
Option 5 → 7.01 g
Explanation:
Molarity . volume (L) = Moles
This can help us to determine the moles of KOH that are in the solution.
We convert the volume from mL to L → 250 mL . 1L / 1000mL = 0.250 L
0.5 mol /L . 0.250L = 0.125 moles of KOH
Now, we only have to convert the moles to mass, by the molar mass:
Moles . molar mass = mass → 0.125 mol . 56.1 g/mol = 7.01 g
Atomic weight of a Platinum:
195.078 u = 195.078 * 1.66 * 10^(-27) kg = 3.2382948 * 10^(-25) kg
m ( Pt ) = 3.2382948 * 10^(-25) * 5.35 * 10^(21) =
= 1.732488 * 10^(-3) kg = 1.732448 g
