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nordsb [41]
3 years ago
11

a sample of concentrated nitric acid has a density of 1.41g/ml and contains 70.0% HNO3 by mass. what mass of HNO3 is present per

liter of solution.
Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
8 0
If you assume you have just 1 liter of sample, you can calculate the mass.
1000mL x 1.4g/mL = 1410g
and 70% of that would be the nitric acid.
Multiplying 1410 by 0.7 would give you 987g, and converting that to moles would give you 15.67M.
Hope this helped! :)
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Answer :

Example of polar covalent molecules H-O-H(water), ammonia

Explanation:

The presence of intermolecular Hydrogen bonding makes the boiling point of water unexpectedly high, and the polar covalent nature makes it dissolve polar solute/compound

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As a child (with a mass of 35.0 kg) you take your 5.0-kg sled to Orchard Downs. If you are sliding down the hill on your sled, w
alukav5142 [94]

Velocity = 3.61 m/s

<h3>Further explanation</h3>

Given

mass of child = 35 kg

mass of sled = 5 kg

Kinetic energy = 260 J

Required

velocity

Solution

Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

KE = 1/2.mv²

mass of object :

= mass child + mass sled

= 35 kg + 5 kg

= 40 kg

Input the value :

v²=KE : 1/2.m

v²= 260 : 1/2.40 kg

v²=13

v=3.61 m/s

3 0
3 years ago
Phenol red is an indicator that changes color over a range from ph=6.4 to ph=8.0. what is ka of phenol red?
patriot [66]
First, we will get the average pH of the two given values:
average pH = (6.4+8) / (2) = 7.2
At this average pH, the concentration of the acid from the phenol red is equal to the concentration of the base.
pH = 7.2
[H+] = 10^(-7.2) = 6.3 * 10^-8

Phenol red has the general formula HA, this gives us:
HA <.......> H+ + A- 
At pH = 7.2, [H+] = [A-]
<span>Ka = [H+][A-]/ [HA]
</span>Ka = [H+] = <span>6.3 x 10^-8</span>

7 0
3 years ago
Which level is made up of organisms that break down dead organisms?
mario62 [17]

Answer:

Explanation:

decomposers

4 0
3 years ago
The freezing point of 42.19 g of a pure solvent is measured to be 43.17 ºC. When 2.03 g of an unknown solute (assume the van 't
vovikov84 [41]

Answer:

The molality of the solution is 0.3716 mol/kg

The number of moles of solute is 0.0157 mol

The molecular weight of the solute is 129.30 g/mol

The molar mass of the solute is 129.32 g/mol

Explanation:

m (molality of the solution) = ∆T/Kf = (43.17 - 40.32)/7.67 = 0.3716 mol/kg

Number of moles of solute = molality × mass of solvent in kilogram = 0.3716 × 0.04219 = 0.0157 mol

Molecular weight of solute = mass/number of moles = 2.03/0.0157 = 129.3 g/mol

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4 0
3 years ago
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