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Lana71 [14]
3 years ago
7

What is the answer? It is very hard was not ther to do it

Chemistry
1 answer:
cricket20 [7]3 years ago
7 0
No idea.. I think if you take angle (<) MNL then divide those...
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What change in volume results if 60 mL of a gas is cooled from 33 C to 5 C?
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Answer:

Change in volume on changing temperature from 33^{\circ}C to 5^{\circ}C is 5.49 mL

Explanation:

Initial volume of gas = V = 60 mL

Assuming final volume of gas to be V' mL

Initial temperature = T = 33^{\circ}C = 306 K

Final temperature = T' = 5^{\circ}C = 278 K

The relationship between volume and temperature of gas at constant pressure is shown below

\displaystyle \frac{V}{V'}=\displaystyle  \frac{T}{T'} \\\displaystyle \frac{60\textrm{ mL}}{V'} = \displaystyle \frac{306\textrm{ K}}{T} \\V' = 54.51 \textrm{ mL} \\\textrm{Change in volume} = \left ( V-V' \right ) \\\textrm{Change in volume} = \left ( 60-54.51 \right )\textrm{ mL} \\\textrm{Change in volume} = 5.49 \textrm{ mL}

Change in volume on changing temperature = 5.49 mL

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