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ycow [4]
2 years ago
10

What is the equation of a circle with center at (3,-4) and radius of 3

Mathematics
1 answer:
koban [17]2 years ago
8 0

Answer:

\displaystyle [x - 3]^2 + [y + 4]^2 = 9

Explanation:

Accourding to one of the circle equations, \displaystyle [x - h]^2 + [y - k]^2 = r^2,the centre of the circle is represented by \displaystyle [h, k].Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared.

I am joyous to assist you at any time.

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3 years ago
Picking a month of the year in the day of the week (fundamental counting principle)
inysia [295]
Since you mentioned the fundamental counting principle, I assume you are looking for the total number of possibilities.

If you are picking a month, there are 12 options.
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8 0
3 years ago
15
Evgesh-ka [11]

Answer:

Height = 14.4

Step-by-step explanation:

The diagonals meet at right angles. Interesting property.

The hypotenuse is the side of the rhombus = 15 cm

One of the sides of the small triangles created by the intersection of the diagonals = 24/2 = 12

You can find the other side of the the triangle by using the Pythagorean Theorem

a^2 + b^2 = c^2

c = 15

a = 12

b = ?

12^2 + b^2 = 15^2

144 + b^2 = 225

b^2 = 225 - 144

b^2 = 81

b = 9

The area of this right angle = 9 * 12/2 = 54

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That's the area of the rhombus.

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3 years ago
Which of the following is a valid exclusion for the algebraic expression
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Answer:

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Step-by-step explanation:


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