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kolbaska11 [484]
3 years ago
11

Can someone please help me with this math question

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Answer:

Step-by-step explanation:

A). From the table of relative frequencies,

Let the relative frequency of women who prefer mineral water = x

Total of relative frequencies of women preferring purified water and mineral water = 0.59

Since, Total of relative frequencies of women who prefer purified water and mineral water = Relative frequency of women preferring purified water + Relative frequency of women preferring mineral water

0.59 = 0.14 + x

x = 0.59 - 0.14

x = 0.45

B). Relative frequency of men  who prefer mineral water = 0.13

Let the frequency of men who prefer mineral water = x

Since, relative frequency = \frac{\text{Frequency}}{\text{Total of frequencies}}

0.13 = \frac{x}{200}

x = 200 × 0.13

x = 26

Therefore, number of shoppers who are men and prefer mineral water = 26

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7 0
3 years ago
Joeff charges 20$ flat rate plus 27$ per hour to work on cars. how many dollars does joeff earn for a 5 hour job?
Ket [755]
Answer is $155 for the job

Step by step

You can use y intercept formula for this one.

Y = mx + b
Y = Dollars earned, what you are looking for.
M= rate per hour (27)
X = hours worked (5)
B = flat rate (20)

y = (27) (5) + 20

y = $155

Problem solved!
7 0
2 years ago
please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

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3 years ago
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