A bag contains marbles: 5 red, 2 blue, and 1 green. You pick a marble and then another one without replacement. What is the prob ability you will draw a red and then a green?
1 answer:
hi
1st draw: green
2/12. (2 green out of 12 marbles), reduces to 1/6
2nd draw: blue
4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)
Probability of theses BOTH happening: multiply these individual probabilities.
Conditional probability:
P(a and b) = P(a)P(b|a)
Prob(event 1) × Prob(event 2 given event 1).
1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.
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