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kodGreya [7K]
3 years ago
6

Dans school is planning a field trip to a museum. Bus company A charges a $40 rental fee plus $4 for each student. Bus company B

charges $100 plus $2 per student. How many students would have to go for the cost to be the same?
Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

30 students would have to go for the cost to be the same.

Step-by-step explanation:

Bus A: $40 + ($4 * 30) = $160

Bus B: $100 + ($2 * 30) = $160

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John has a circular pool that has a radius of 7 feet. What is the area of his pool? Please use the formula sheet to assist you w
andrew-mc [135]

Answer:

153.86 square feet

Step-by-step explanation:

The formula for the area of a circle is A=πr2

area = pi x radius squared

the radius is 7 feet, square that to get 49

multiply 49 by pi to get the area: 153.86 square feet

5 0
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What is the area of the trapezoid?
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To find the area of the trapezoid you add the two bases then multiply by the base and divide by 2. 

B1+b2= 24+16=40
40*h=40*12=480
480/2=240

D. 240 square feet.
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What did Tarzan like to play?
Mazyrski [523]

Answer:

Step-by-step explanation:

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How do you write 0.4716 as a percentage?
wolverine [178]

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2.9375% Rounded or 2.94% not rounded

Step-by-step explanation:

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Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
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