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sveticcg [70]
4 years ago
7

Simplify the expression: -12u +12u + 8

Mathematics
1 answer:
Olenka [21]4 years ago
8 0

Answer:

8

Step-by-step explanation:

-12u and 12u cancel each other out. Leaving 8 by itself.

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three of the names do not belong in this box. cross them out. write the name of the number on the top box.
mario62 [17]

Answer:

the number is 12

Step-by-step explanation:

20 - 7, 40 - 23, and 4 x 4

3 0
4 years ago
Two positive integers are 3 units apart on a number line. Their product is 108.
SVETLANKA909090 [29]

Answer:

d)  the numbers are 9 and 12

Step-by-step explanation:

set each factor equal to 108:

m-12=108

m = 120

*************

m-9=108

m=117

*************

120 and 117 are 3 units apart

****************

9 x 12 = 108

7 0
3 years ago
Use the definition of the derivative to differentiate f(x)= In x
WINSTONCH [101]

By def. of the derivative, we have for y = ln(x),

\displaystyle \frac{dy}{dx} = \lim_{h\to0} \frac{\ln(x+h)-\ln(x)}{h}

\displaystyle \frac{dy}{dx} = \lim_{h\to0} \frac1h \ln\left(\frac{x+h}{x}\right)

\displaystyle \frac{dy}{dx} = \lim_{h\to0} \ln\left(1+\frac hx\right)^{\frac1h}

Substitute y = h/x, so that as h approaches 0, so does y. We then rewrite the limit as

\displaystyle \frac{dy}{dx} = \lim_{y\to0} \ln\left(1+y\right)^{\frac1{xy}}

\displaystyle \frac{dy}{dx} = \frac1x \lim_{y\to0} \ln\left(1+y\right)^{\frac1y}

Recall that the constant e is defined by the limit,

\displaystyle e = \lim_{y\to0} \left(1+y\right)^{\frac1y}

Then in our limit, we end up with

\displaystyle \frac{dy}{dx} = \frac1x \ln(e) = \boxed{\frac1x}

In Mathematica, use

D[Log[x], x]

5 0
3 years ago
Anyone wanna talk with me
QveST [7]

Answer:

yea i wanna talk :)

just comment below

8 0
3 years ago
Read 2 more answers
The functions f(x) = (x + 1)2 − 2 and g(x) = −(x − 2)2 + 1 have been rewritten using the completing-the-square method. Apply you
galina1969 [7]

Answer:

f(x)=(x+1)^2-2 is the minimum and g(x)=-(x-2)^2+1 is the maximum

Step-by-step explanation:

Looking at the graph, (you should be able to graph this) the parabola for f(x)=(x+1)^2-2 is pointing downwards and stops at the vertex. This vertex is negative which is the lowest point possible which makes it the minimum. The parabola for -(x-2)^2+1 is pointing upwards and stops at the vertex which is the highest point possible which makes it the maximum.

8 0
3 years ago
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