Answer:
d is correct
Step-by-step explanation:
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
B
Step-by-step explanation:
use quadratic formula: (-b ±√b²-4ac) ÷ 2a
a = 10, b = -9, c = -6
Given:
The given sets are:
Set a : 200, 104, 100, 160.
Set b: 270, 400, 483, 300, x.
Mean of set a: mean of set b= 3:8
To find:
The value of x.
Solution:
Formula for mean:
The mean of set of a is:
The mean of set of b is:
It is given that,
Mean of set a: mean of set b= 3:8
Isolate the variable x.
Divide both sides by 3.
Therefore, the value of x is 427.
Answer:
Step-by-step explanation:
The origin (x,y) is (0,0)
If its moved four units right you must add 4 to the x coordinate giving you (4,0)
Then it is moved up by 5, so you must add 5 to the y coordinate giving you
(4,5)
