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Charra [1.4K]
3 years ago
9

a jet flying at an altitude of 30000 ft passes over a small plane flying at 15000 feet headed in the same direction the jets fly

ing twice as fast as a small plane and 45 minutes later they are 450 miles apart find the speed of each plane
Mathematics
1 answer:
Sholpan [36]3 years ago
8 0

The jet has gained on the small plane at the rate of 10 miles per minute, so is flying 600 miles per hour faster. (There are 60 minutes in an hour.)

Since the jet is flying twice as fast as the smaller plane, the small plane's speed is the same as the difference in speed: 600 mph.

The jet's speed is double that, 1200 mph.

  • small plane: 600 mph
  • jet: 1200 mph
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Step-by-step explanation:

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Triangles P Q R and S T U are shown. Angles P R Q and T S U are right angles. The length of P Q is 20, the length of Q R is 16,
dimaraw [331]

Answer:

\angle P

Step-by-step explanation:

Given

\triangle PRQ = \triangle TSU = 90^o

PQ = 20     QR = 16    PR = 12

ST = 30       TU = 34    SU = 16

<em>See attachment</em>

Required

Which sine of angle is equivalent to \frac{4}{5}

Considering \triangle PQR

We have:

\sin(P) = \frac{QR}{PQ} --- i.e. opposite/hypotenuse

So, we have:

\sin(P) = \frac{16}{20}

Divide by 4

\sin(P) = \frac{4}{5}

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\angle P is correct

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3 years ago
What is the volume of the cylinder below? A cylinder with a height of 12 millimeters and diameter of 18 millimeters. 108 pi mm3
Artemon [7]

Answer:

V =972 pi mm ^3

Step-by-step explanation:

The diameter is 18 so the radius is 1/2 of the diameter

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V = pi r^2 h

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A boat starts in Wilmington and sails 5 miles due east and then 3 miles due south. What is the approximate shortest distance bac
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Step-by-step explanation:

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3 years ago
Imagine that you would like to purchase a $275,000 home. Using 20% as
vfiekz [6]

Answer:

The mortgage chosen is option A;

15-year mortgage term with a 3% interest rate because it has the lowest total amount paid over the loan term of $270,470

Step-by-step explanation:

The details of the home purchase are;

The price of the home = $275,000

The mode of purchase of the home = Mortgage

The percentage of the loan amount payed as down payment = 20%

The amount used as down payment for the loan = $55,000

The principal of the mortgage borrowed, P = The price of the house - The down payment

∴ P = $275,000 - 20/100 × $275,000 = $275,000 - $55,000 = $220,000

The principal of the mortgage, P = $220,000

The formula for the total amount paid which is the cost of the loan is given as follows;

Outstanding \ Loan \ Balance = \dfrac{P \cdot \left[\left(1+\dfrac{r}{12} \right)^n -  \left(1+\dfrac{r}{12} \right)^m \right] }{1 - \left(1+\dfrac{r}{12} \right)^n }

The formula for monthly payment on a mortgage, 'M', is given as follows;

M = \dfrac{P \cdot \left(\dfrac{r}{12} \right) \cdot \left(1+\dfrac{r}{12} \right)^n }{\left(1+\dfrac{r}{12} \right)^n - 1}

A. When the mortgage term, t = 15-years,

The interest rate, r = 3%

The number of months over which the loan is payed, n = 12·t

∴ n = 12 months/year × 15 years = 180 months

n = 180 months

The monthly payment, 'M', is given as follows;

M =

The total amount paid over the loan term = Cost of the mortgage

Therefore, we have;

220,000*0.05/12*((1 + 0.05/12)^360/( (1 + 0.05/12)^(360) - 1)

M = \dfrac{220,000 \cdot \left(\dfrac{0.03}{12} \right) \cdot \left(1+\dfrac{0.03}{12} \right)^{180} }{\left(1+\dfrac{0.03}{12} \right)^{180} - 1}  \approx 1,519.28

The minimum monthly payment for the loan, M ≈ $1,519.28

The total amount paid over loan term, A = n × M

∴ A ≈ 180 × $1,519.28 = $273,470

The total amount paid over loan term, A ≈ $270,470

B. When t = 20 year and r = 6%, we have;

n = 12 × 20 = 240

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.06}{12} \right) \cdot \left(1+\dfrac{0.06}{12} \right)^{240} }{\left(1+\dfrac{0.06}{12} \right)^{240} - 1}  \approx 1,576.15

The total amount paid over loan term, A = 240 × $1,576.15 ≈ $378.276

The monthly payment, M = $1,576.15

C. When t = 30 year and r = 5%, we have;

n = 12 × 30 = 360

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.05}{12} \right) \cdot \left(1+\dfrac{0.05}{12} \right)^{360} }{\left(1+\dfrac{0.05}{12} \right)^{360} - 1}  \approx 1,181.01

The total amount paid over loan term, A = 360 × $1,181.01 ≈ $425,163

The monthly payment, M ≈ $1,181.01

The mortgage to be chosen is the mortgage with the least total amount paid over the loan term so as to reduce the liability

Therefore;

The mortgage chosen is option A which is a 15-year mortgage term with a 3% interest rate;

The total amount paid over the loan term = $270,470

8 0
3 years ago
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