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Mashcka [7]
3 years ago
15

Distance of the point P(3,-4) from the oirgin is?

Mathematics
2 answers:
krek1111 [17]3 years ago
5 0

<u>Answer:</u>

Distance between origin and point P(3, -4) is 5 units.    

<u>Solution:</u>

We need to find distance between origin and point P (3, -4) .

We will be using distance formula.  According to the distance formula , distance d between two points  \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

In given case two points are  O ( 0 , 0 )  (origin) and  P( 3 , -4) .  

On applying distance formula  

\begin{aligned} \mathrm{OP} &=\sqrt{(3-0)^{2}+((-4)-0)^{2}} \\ &=\sqrt{3^{2}+(-4)^{2}} \\ &=\sqrt{9+16} \\ &=\sqrt{25} \end{aligned}

So OP = 5 units

Hence distance between origin and point P(3, -4) is 5 units.     

Naily [24]3 years ago
4 0

Answer:Answer: point (3,-4) is 3 units to the right of the origin and 4 down

Step-by-step explanation: easiest to graph

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Answer:

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Step-by-step explanation:

u(-5, 7) ; v(6 , -2) ;   w(-11,4)

4v - 7w = (4*6+[-7]*[-11] , 4*[-2] + [-7]*4)

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4v - 7w  = (101 , -36)

6u - 8v = (6*[-5]+[-8]*6 , 6*7+[-8]*[-2] )

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6u -8v = (-78 , 58)

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2u +v - 4w = (40 , -4)                  

11u + 3w = (11*[-5]+3*[-11]  ,  7*11 +3*4)

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Identify the domain of the function shown in the graph
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Using it's concept, the domain of the function shown in the graph is:

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<h3>What is the domain of a function?</h3>

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From this graph, the function is defined for values of x between -6 and 6, hence the domain is given by:

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When a linear equation is represented as:

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When the linear equation is represented as:

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A line perpendicular to a linear equation that has a slope of m would have a slope of -1/m

Using the above highlights, the equations of the lines are:

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The slope is:

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