Question

Distance of the point P(3,-4) from the oirgin is?

Answer 1

Answer:

Distance between origin and point P(3, -4) is 5 units.    

Solution:

We need to find distance between origin and point P (3, -4) .

We will be using distance formula.  According to the distance formula , distance d between two points  $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

In given case two points are  O ( 0 , 0 )  (origin) and  P( 3 , -4) .  

On applying distance formula  

$\begin{aligned} \mathrm{OP} &=\sqrt{(3-0)^{2}+((-4)-0)^{2}} \\ &=\sqrt{3^{2}+(-4)^{2}} \\ &=\sqrt{9+16} \\ &=\sqrt{25} \end{aligned}$

So OP = 5 units

Hence distance between origin and point P(3, -4) is 5 units.     

Answer 2

Answer:Answer: point (3,-4) is 3 units to the right of the origin and 4 down

Step-by-step explanation: easiest to graph