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mamaluj [8]
2 years ago
6

Last week, the price of apples at a grocery store was $1.06 per pound. This week, apples at the store are on sale at a 10% disco

unt. What is the total price of 4/1/2 pounds of apples this week at the grocery store?
Mathematics
1 answer:
olga2289 [7]2 years ago
4 0

Answer: $6.48

Step-by-step explanation:

1.60 * 0.1 = $0.16

1.60 - 0.16 = $1.44

1.44 * 4.5 = $6.48

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On the weekdays a grocery store has 14239 customers and on the weekends the grocery store has
Vedmedyk [2.9K]

Answer: 2605 more on weekdays

Step-by-step explanation:

14239 - 11634 = 2605

8 0
1 year ago
Find the volume of the cylinder with the info below.
mote1985 [20]

Answer: 141.3 in{3}

1. V = πr{2}h

2. V = (3.14)(3{2})(5)

3. V = 141.3 in.

Hope this answer helps you!

6 0
3 years ago
Which of the following sets of ordered pairs represents a function?
Zinaida [17]

Shouldn't the answer be: (-1,4),(1,4),(2,4),(-2,4)

8 0
3 years ago
Read 2 more answers
The game commission observes the fish population in a stream and notices that the number of trout increases by a factor of 1.5 e
just olya [345]

Answer:

A - f(t)=80(1.5)^t

B - Graph given below

C - Number of trouts in 5th week are 607.2

D - Population of trouts will exceed 500 on the 5th week.

Step-by-step explanation:

We are given that,

The number of trout increases by a factor of 1.5 each week and the initial population of the trout is observed to be 80.

Part A: So, the explicit formula representing the situation is,

f(t)=80(1.5)^t, where f(t) represents the population of trouts after 't' weeks.

Part B: The graph of the function can be seen below.

It can be seen that the function is an exponential function.

Part C: It is required to find the number of trouts in the 5th week.

So, we have,

f(5)=80(1.5)^5

i.e. f(5)=80\times 7.59

i.e. f(5) = 607.2

Thus, the number of trouts in 5th week are 607.2

Part D: We are given that the trout population exceeds 500.

It is required to find the week in which this happens.

So, we have,

50

i.e. (1.5)^t>\frac{500}{80}

i.e. (1.5)^t>6.25

i.e. t\log 1.5>\log 6.25

i.e. t\times 0.1761>0.7959

i.e. t>\frac{0.7959}{0.1761}

i.e. t > 4.5

As, t represents the number of weeks. So, to nearest whole, t = 5.

Thus, the population of trouts will exceed 500 on the 5th week.

7 0
3 years ago
Solve the equation by completing the square. Show your work.<br> v^2-8v-59=-2
Debora [2.8K]

Answer:

answer is {-4.42, 12.54}


Step-by-step explanation:

v^2 - 8v - 59 = -2

v^2 - 8v = 57

(v - 4)^2 - 16 = 57

(v - 4)^2 = 73

Taking square roots:-

v - 4  = +/- √73

v = √73 + 4 or - √73 + 4

v = -4.54 , 12.54

3 0
3 years ago
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