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JulijaS [17]
3 years ago
13

Find the 5th term Thank you in advance

Mathematics
1 answer:
Ksju [112]3 years ago
3 0
T1 = 3
t2 = 2*t1 = 6
t3 = 2*t2 = 12
t4 = 24
t5 = 48
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Tan9°. tan27°. tan45°. tan72°. tan81°= 1​<br><br>could u plz solve it with clear process
Inga [223]

<u>Correct</u><u> </u><u>question</u><u>:</u><u>-</u>

<u>Prove </u><u>that </u><u>tan9.</u><u>t</u><u>a</u><u>n</u><u>1</u><u>7</u><u>.</u><u>t</u><u>a</u><u>n</u><u>4</u><u>5</u><u>.</u><u>t</u><u>a</u><u>n</u><u>7</u><u>3</u><u>.</u><u>t</u><u>a</u><u>n</u><u>8</u><u>1</u><u>=</u><u>1</u>

<u>LHS</u>

\\ \sf\longmapsto tan9.tan17.tan45.tan73.tan81

\\ \sf\longmapsto tan9.tan81.tan17.tan73.tan45

\\ \sf\longmapsto tan(90-81).tan81.tan(90-73).tan73.1

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\\ \sf\longmapsto 1.1

\\ \sf\longmapsto 1

5 0
2 years ago
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DaniilM [7]

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Answer:

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Given Statement: Fred is running on the school track. He can run 10\frac{3}{4}  laps in \frac{4}{5}  of an hour.

Unit rate are expressed as a quantity of 1, such as 3 feet per second or 7 miles per hour, they are called unit rates

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Therefore, Fred can run in one hour is, 13\frac{7}{16} laps.

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