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vazorg [7]
3 years ago
11

Kelsey graphed the equation y = 3x + 1 as shown below.

Mathematics
2 answers:
siniylev [52]3 years ago
7 0
Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.

dalvyx [7]3 years ago
6 0

The given equation of line in two variable is :

→y = 3 x +1

→→It is the slope intercept form of line having slope = 3 ,

and Y intercept = 1.

→→→Slope of line = Tan (theta)=3, i.e Angle made by line in positive direction of X axis.

we can draw its graph by taking any two points on the line

put , x= 0 gives y=1.

Put y=0, gives , x = \frac{-1}{3}  

So we will draw equation of line joining (0,1) and (\frac{-1}{3},0).

Or convert it into  intercept form which is :  \frac{x}{\frac {-1}{3}}+\frac{y}{1}=1

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A triangle with a base of 5 inches a height of 4 inches.
Degger [83]

Answer:

If your asking if your work is correct, its not.

Each triangle has an area of 10 inches

the total area of the placemat is 420 inches

Step-by-step explanation:

Formula for area of a triangle is \frac{1}{2} b · h

7 0
3 years ago
Read 2 more answers
A train traveling nonstop to its destination is able to make the trip at an average speed of 70 miles per hour. On the return tr
larisa86 [58]

Answer:

Return trip travel time: 7h

Step-by-step explanation:

Let d be the distance.

Index 1 refers to initial trip, index 2 refers to the return trip.

v1=70mi/h

v2=40mi/h

t2=t1+3h, or t1=t2-3h (travel times)

d=v1×t1=v2×t2

v1×(t2-3)=v2×t2

v1 t2 -3 v1=v2 t2

v1 t2 - v2 t2=3 v1

t2(v1-v2)=3v1

t2=3v1/(v1-v2)

Or

t2=3×70/(70-40)=3×70/30=7h

3 0
3 years ago
The model below represents an equation. Write the equation that is modeled then find what value of x makes the equation true.
Dimas [21]
6x-5=4x+5
+5

6x=4x + 0
-4x
2x=0
x =0

probably to late but whatever

4 0
3 years ago
Enter an equation in the form of y = MX + b that represents the function described by the graph ​
Molodets [167]

Answer:

y=2/3+3

Step-by-step explanation:

3 0
3 years ago
Rewrite the function in standard form, intercept form, find the vertex, find the y-intercept, and find the x-intercepts.
jasenka [17]

Answer:

We have the function, f(x)=(x+3)^{2}-4

On simplifying, we get,

f(x)=x^2+6x+9-4

i.e. f(x)=x^2+6x+5

Thus, the standard form of the function is f(x)=x^2+6x+5.

Now, the factors of the given functions are (x+1) and (x+5).

<em>Since, the intercept form of the function is the factored form of the function.</em>

So, we have, intercept form of the function is f(x)=(x+1)(x+5).

Now, we know that,

Value of x-coordinate of the vertex is \frac{-b}{2a} i.e. \frac{-6}{2\times 1} i.e. \frac{-6}{2} i.e. x= -3

Then, f(-3)=(-3)^2+6\times (-3)+5 i.e. f(-3)=9-18+5 i.e. f(-3)=-4

So, the vertex of the function is (-3,-4).

Further, we know that,<em> 'the y-intercept of a function is the point where the function crosses y-axis'.</em>

So, when x=0, we have, f(0)=0^2+6\times 0+5 i.e. f(0) = 5

Thus, the y-intercept is (0,5)

Also, <em>'the x-intercept of a function is the point where the function crossese x-axis'.</em>

Then, for f(x)=0, we have 0=x^2+6x+5 i.e. 0=(x+1)(x+5) i.e. x= -1 and x= -5

Thus, the x-intercept are (-1,0) and (-5,0).

8 0
3 years ago
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