All categories

3 years ago

If a bug with a mass of 5 grams flies into the windshield of a moving 1000 kg bus, which will have the most force?

Physics

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:its a equal force

Explanation:

You might be interested in

The chart shows data for four heat engines

lesantik [10]

Where is it lollllll

8 0

3 years ago

A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic f

skad [1K]

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

$B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}$

$B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T$

3 0

3 years ago

A car is driving towards an intersection when the light turns red. The brakes apply a constant force of 1,398 newtons to bring t

dmitriy555 [2]

Answer:

the initial velocity of the car is 12.04 m/s

Explanation:

Given;

force applied by the break, f = 1,398 N

distance moved by the car before stopping, d = 25 m

weight of the car, W = 4,729 N

The mass of the car is calculated as;

W = mg

m = W/g

m = (4,729) / (9.81)

m = 482.06 kg

The deceleration of the car when the force was applied;

-F = ma

a = -F/m

a = -1,398 / 482.06

a = -2.9 m/s²

The initial velocity of the car is calculated as;

v² = u² + 2ad

where;

v is the final velocity of the car at the point it stops = 0

u is the initial velocity of the car before the break was applied

0 = u² + 2(-a)d

0 = u² - 2ad

u² = 2ad

u = √2ad

u = √(2 x 2.9 x 25)

u =√(145)

u = 12.04 m/s

Therefore, the initial velocity of the car is 12.04 m/s

7 0

3 years ago

An airplane in the earth’s magnetic field can develop a voltage between its wingtips.

Svetradugi [14.3K]

Answer:

$emf=0.125\ V$

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

Explanation:

Given:

velocity of plane, $v=250\ m.s^{-1}$

magnetic field, $B=5\times 10^{-5}\ T$

angle between velocity and magnetic field, $\theta=30^{\circ}$

span of the wing, $l=20\ m$

We know:

$emf=B.l.v\ sin\theta$

$emf=5\times 10^{-5}\times 20\times 250\times sin30^{\circ}$

$emf=0.125\ V$

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

7 0

3 years ago

Find the weight of a 60 kg astronaut on earth.<br> (Pls help)

ollegr [7]

Answer:

IT is 120 kg

Explanation:

7 0

3 years ago