Question

A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic field (magnitude and direction) at the point x=5m on the x-axis.

Answer 1

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

$B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}$

$B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T$