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Marat540 [252]
3 years ago
7

An airplane in the earth’s magnetic field can develop a voltage between its wingtips.

Physics
1 answer:
Svetradugi [14.3K]3 years ago
7 0

Answer:

emf=0.125\ V

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

Explanation:

Given:

  • velocity of plane, v=250\ m.s^{-1}
  • magnetic field, B=5\times 10^{-5}\ T
  • angle between velocity and magnetic field, \theta=30^{\circ}
  • span of the wing, l=20\ m

We know:

emf=B.l.v\ sin\theta

emf=5\times 10^{-5}\times 20\times 250\times sin30^{\circ}

emf=0.125\ V

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

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Answer:

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(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

Explanation:

Given that,

Maximum potential = 4.00 mV

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Frequency = 1.00 Hz

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\Delta V=Ed

E=\dfrac{\Delta V}{d}

E=\dfrac{4.00\times10^{-3}}{0.300}

E=0.0133\ V/m

(b). We need to calculate the maximum magnetic field strength in the electromagnetic wave

Using formula of the maximum magnetic field strength in the electromagnetic wave

B=\dfrac{E}{c}

Put the value into the formula

B=\dfrac{0.0133}{3\times10^{8}}

B=4.433\times10^{-11}\ T

(c). We need to calculate the wavelength of the electromagnetic wave

Using formula of wavelength

c=f\lambda

\lambda=\dfrac{c}{f}

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{1.00}

\lambda=3\times10^{8}\ m

Hence, (a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

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Answer:

The wavelength is \lambda  =  1.2  * 10^8 nm

Explanation:

From the question we are told that

   The frequency of operation of the microwave is  f =  2.50 GHz  =  2.50 *10^{9} \ Hz

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