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Bad White [126]
3 years ago
13

Using the information in the Venn diagram below, how many people play basketball? A. 5 B. 9 C. 12 D. 17 4 D. 5

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

52 people

Step-by-step explanation:

add 5 9 12 17 4 5 and youlk get 52 people.

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iragen [17]
They are actually the same.....Hope this helped you!!
7 0
3 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
2 1/2 divided by 1 5/8? I forgot how to divide fractions and simplify them....please help
nlexa [21]
2\frac{1}{2}:1\frac{5}{8}=\frac{2\times2+1}{2}:\frac{1\times8+5}{8}=\frac{5}{2}:\frac{13}{8}=\frac{5}{\not2_1}\times\frac{\not8^4}{13}=\frac{5}{1}\times\frac{4}{13}=\frac{5\times4}{1\times13}=\frac{20}{13}=1\frac{7}{13}
3 0
3 years ago
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A total of 243 adults and children are at a movie theater. There are 109 more adults than children in the theater. If eh represe
Marina86 [1]
The system should look like this:

eh + b = 243
eh - b = 109
6 0
4 years ago
Round 584,565 to the nearest hundred thousand.
lora16 [44]

Answer:

600,000

Step-by-step explanation:

600,000

600,000

600,000

600,000

8 0
4 years ago
Read 2 more answers
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