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amid [387]
3 years ago
13

Point M is located at (4,6) on a coordinate grid. Point M is translated 8 units to thr left and 9 units down to create point M'.

Which measurement is closest to the distance between point M and point M' in units?
Mathematics
1 answer:
nata0808 [166]3 years ago
4 0
Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!

We have the point 4,6. 4 is the x, and 6 is the y.

Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.

Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.

So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!

The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²

Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.

So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.

So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²

Solving it out, we first need to work within the parenthesis. Can you solve it?

Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²

8²= 64
9²= 81

64+81 = 145.

So, the distance between point M and point M' would be 145 units

Hope this helps!

If it does not, please let me know so i can try to help!

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morpeh [17]

Answer:

Correct option is

B

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6 0
3 years ago
In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.
bezimeni [28]

Given:

In the circle, m(\overarc{VUX})=152^\circ and m(\angle MUV)=77^\circ.

To find:

The following measures:

(a) m\angle VUX

(b) m\angle UXW

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

m(VUX)=2\times m\angle VWX

152^\circ=2\times m\angle VWX

\dfrac{152^\circ}{2}=m\angle VWX

76^\circ=m\angle VWX

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

m\angle VUX+m\angle VWX=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle VUX+76^\circ=180^\circ

m\angle VUX=180^\circ-76^\circ

m\angle VUX=104^\circ

Now,

m\angle UXW+m\angle UVW=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle UXW+77^\circ =180^\circ

m\angle UXW=180^\circ-77^\circ

m\angle UXW=103^\circ

Therefore, m\angle VUX=104^\circ  and m\angle UXW=103^\circ .

7 0
3 years ago
Jim washes 2/3 of his car with 1/2 a bottle of soap. What fraction of the soap will he use to clean his entire car?​
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so to clean the last 1/3 of the car, he`ll use 1/4 of the remaining soap

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KatRina [158]
Using PEMDAS,
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4 years ago
Read 2 more answers
Help would be appreciated :)
Orlov [11]

Answer:

3y-x=-18

Step-by-step explanation:

3y-x=-18

3y=x-18

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