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3 years ago

The hopper bin in the picture below is modeled by the two-dimensional figure beside it. The hopper bin is

Mathematics

1 answer:

Zepler [3.9K]3 years ago

4 0

The volume of the hopper bin is the amount of feed in it

The volume of the hopper bin is 35974 cubic feet
The carnival tent can be filled to 85% of its volume and not exceed the weight limit

<h3>The volume of the hopper bin</h3>

The given parameters are:

Height of cylinder, H = 20 ft
Diameter of cylinder, D = 36 feet
Angle, θ = 52°

Start by calculating the radius (r) of the cones.

r = D/2 -------- because the cones and the cylinder have equal diameters.

So, we have:

r = 36/2 = 18

The height (h) of the cones is:

tan(θ) = h/r

This gives

tan(52) = h/18

Make h the subject

h = 18 * tan(52)

Evaluate

h = 23.04

The volume is then calculated as:

Volume = Volume of cylinder + 2 * Volume of cone

This gives

Volume = πr^2H + 2 * 1/3πr^2h

Volume = πr^2H + 2/3πr^2h

Factor out πr^2

Volume = πr^2(H + 2/3h)

Substitute known values

Volume = 3.14 * 18^2 * (20 + 2/3 * 23.04)

Evaluate

Volume = 35973.85 cubic feet

Hence, the volume of the hopper bin is 35974 cubic feet

<h3>The weight limit of the hopper bin</h3>

The given parameters are:

Maximum weight = 500000 pounds
Feed weight = 22 pounds per cubic feet

For a feed that weighs 22 pounds per cubic feet, the weight of the hopper bin would be:

Weight = 22 * 35974 pounds

Weight = 791428 pounds

At 85% full, the weight wuld be:

Weight = 85% * 791428 pounds

Weight = 672713.8 pounds

672713.8 pounds is greater than the weight limit of 500000 pounds.

Hence, the carnival tent can be filled to 85% of its volume and not exceed the weight limit

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3 years ago

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Step-by-step explanation:

Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. The mean absolute deviation, MAD, is 2.

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2 years ago

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$V_F=\frac{343}{3}\pi+294\pi=\frac{343}{3}\pi+\frac{294\cdot3}{3}\pi=\frac{343}{3}\pi+\frac{882}{3}\pi=\boxed{\frac{1225}{3}\pi\ (ft^3)}\\\\\approx\frac{1225}{3}\cdot3.14}=\frac{3846.5}{3}\approx\boxed{1,282.17\ (ft^3)}\leftarrow answer$

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