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2 years ago

What is the rate of change between (2,2) and (17,7)

Mathematics

1 answer:

ziro4ka [17]2 years ago

6 0

Answer:

$\frac{1}{3} = m$

Step-by-step explanation:

$\frac{-y_1 + y_2}{-x_1 + x_2} = m$

$\frac{-2 + 7}{-2 + 17} = \frac{5}{15} = \frac{1}{3}$

I am joyous to assist you anytime.

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Triangle ABC has vertices at A(-4, -2), B(1, 7) and C(8, -2)

Arada [10]

Answer:

a). Area = 54 square units

b). Perimeter = 33.7 units

Step-by-step explanation:

Vertices of the triangle ABC are A(-4, -2), B(1, 7) and C(8, -2).

(a). Area of the triangle ABC = $\frac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$ (Absolute value)

By substituting the values from the given vertices,

Area = $\frac{1}{2}[(-4)(7+2)+(1)(-2+2)+8(-2-7)]$

= $\frac{1}{2}[-36+0-72]$

= $\frac{1}{2}(-108)$

= (-54) unit²

Therefore, absolute value of the area = 54 square units

(b). Distance between two vertices (a, b) and (c, d)

d = $\sqrt{(a-c)^{2}+(b-d)^2}$

AB = $\sqrt{(-4-1)^{2}+(-2-7)^{2}}$

= $\sqrt{106}$

= 10.295 units

BC = $\sqrt{(1-8)^2+(7+2)^2}$

= $\sqrt{130}$

= 11.402 units

AC = $\sqrt{(-4-8)^2+(-2+2)^2}$

= 12 units

Perimeter of the triangle = AB + BC + AC = 10.295 + 11.402 + 12

= 33.697

≈ 33.7 units

7 0

3 years ago

Three tables are placed side by side. One table is 2 feet 2 inches wide, another is 4 feet 9 inches wide, and the third is 2 fee

Elena-2011 [213]

Nine feet ten inches hopes this helped

3 0

2 years ago

Please help A 35 B 62 C 25 D 40

zvonat [6]

Answer: 35

Step-by-step-explanation:
There are 20 numbers. So, it would be 7 divided by 20. Which is 0.35. And 0.35 multiply by 100 is 35.

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2 years ago

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adoni [48]

Express 0.31 as a fraction and express 0.2 as a fraction

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3 years ago

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brilliants [131]

Answer:

I dont know if this is right but I think its 125/343

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2 years ago