What z score in a normal distribution has 33% of all score above it?
Answer: A z score which has 33% of all scores above it, will have 67% of all scores below it.
To find the required z score, we need to find the z value corresponding to probability 0.67.
Using the standard normal table, we have:
Therefore, the z score = 0.44 has 33% of all score above it.
Answer:
True
Step-by-step explanation:
Why true I had that problem and it was true.
Answer:-9,015.23 i think plz dont come at me if wrong
Step-by-step explanation:
5+5=10/6=1.6*100=166.6/(25+1000=1025)=0.16-3456=-3,455.84*60=-207,350.4/23=-9,015.23
Answer: (A) 19.3%
<u>Step-by-step explanation:</u>
Vodka + Vermouth + Olive = Total Cost
$2.59 + $0.12 + $0.15 = $2.86
<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
