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scoundrel [369]

2 years ago

11

HELP!!! Is this a function or not a function Why or why not

1 answer:

defon2 years ago

6 0

Answer:

Yes, it is a function

Step-by-step explanation:

anytime you want to test to see if the graph is a function, perform a vertical line test.

Basically if you drew a vertical line and the vertical line crosses the graph at only one point that means the graph is a function.

If it crosses on more than one point the graph is not a function.

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What property out of distributive,communitive,and associative.

Vlad1618 [11]

Hello!

The Associative Property of Multiplication states the following:

a × (b × c) = (a × b) × c

The equation given in the image above follows the same form:

9 × (5 × 2) = (9 × 5) × 2

Therefore, the given equation must be representative of the Associative Property.

I hope this helps!

7 0

3 years ago

If f(x)=-x+2, find f(4)

pickupchik [31]

Answer:

f(4)=-2

Step-by-step explanation:

f(4)=-4+2=-2

5 0

3 years ago

Consider the geometric sequence: 3, 15, 75, 375, 1875 ... 1. What is the constant ratio, r, for this sequence? 2. Use r to write

zalisa [80]

R= 5

$a_{n} =3* 5^{n-1}$

7 0

3 years ago

Read 2 more answers

PSYCHO15rus [73]

Answer:

74676.

Step-by-step explanation:

Lets try multiplying 127 by 294 ( 127 is a prime number):

127 * 294 = 37338.

37338 / 196 = 190.5

37338 * 2 = 74676 which will now be divisible by 196.

74676 will be divisible by 98, 49 and 7 (because they are factors of 196).

It is also divisible by 84 ( to give 889) and therefore by 42, 28, 21, 14, 12, 6, 4, 3 , 2 and 1 which are all factors of 84.

3 0

3 years ago

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point A(-2,3), we get;

$(-2,3)\rightarrow (-2,-3)$

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

$(0,3)\rightarrow (0,-3)$

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0

3 years ago