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3 years ago

Solve the following simultaneous equations 2x+5y=0 and 3x-4y=23

Mathematics

1 answer:

Elodia [21]3 years ago

7 0

Answer:

x = 5, y = -2

Step-by-step explanation:

2x + 5y = 0 --- Equation 1

Equation 1×3: 6x + 15y = 0 --- Equation 2

3x - 4y = 23 --- Equation 3

Equation 3×2: 6x - 8y = 46 --- Equation 3

We will be eliminating 6x from Equation 2.

Equation 3-2: 6x - 8y - 6x - 15y = 46-0

-23y = 46

y = 46 ÷ -23

y = -2

Substitute y = -2 into Equation 1:

2x + 5y = 0

2x + 5(-2) = 0

2x + (-10) = 0

2x - 10 = 0

2x = 10

x = 10 ÷ 2

x = 5

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Step-by-step explanation:

Consider the provided information.

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4 years ago

I need help with this one

sammy [17]

The correct answer is C, 6.15

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How do you factor n^3+1000

marysya [2.9K]

N^3 + 1000
Steps
you have to apply the sum of cubes rule: x^3 + y^3 = (x + y)(x^2 - xy + y^2)
which is... n^3 + 1000 = (n + 10)(n^2 - 10n + 10^2)
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3 years ago