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Delvig [45]
3 years ago
7

The expression (4c − 3d)(3c + d) is equivalent to:

Mathematics
1 answer:
Umnica [9.8K]3 years ago
4 0

(4c - 3d)(3c + d) =

= 12c² + 4cd - 9cd - 3d² =

= <u>12c² - 5cd - 3d²</u>

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2x + y = 12 \\ x = 9 - 2y

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is the answer to:

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3 0
3 years ago
The upper-left coordinates on a rectangle are (-6,0)(−6,0)left parenthesis, minus, 6, comma, 0, right parenthesis, and the upper
nikklg [1K]

Answer:

See attachment for rectangle

Step-by-step explanation:

Given

A = (-6,0)

B = (-4,0)

Area = 12

Required

Draw the rectangle

First, we calculate the distance between A and B using distance formula;

AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

AB = \sqrt{(-6 - -4)^2 + (0- 0)^2}

AB = \sqrt{(-2)^2 + (0)^2}

AB = \sqrt{4 + 0}

AB = \sqrt{4}

AB = 2

The above represents the length of the triangle.

Next, calculate the width using:

Length * Width = Area

2* Width = 12

Divide both sides by 2

Width = 6

This implies that, the width of the rectangle is 6 units.

We have:

A = (-6,0)

B = (-4,0)

Since A and B are at the upper left and right, then the ther two points are below.

6 units below each of the above point are:

C = (-6,0-6)\\ => C = (-6,-6)

D = (-4,0-6) => D = (-4,-6)

Hence, the points of the rectangle are:

A = (-6,0)

B = (-4,0)

C = (-6,-6)

D = (-4,-6)

<em>See attachment for rectangle</em>

6 0
3 years ago
How would you describe this slice that created the square
andreev551 [17]

For anyone else who needs the right answer...it’s “parallel to the base”. I just did it and I got it right.


8 0
3 years ago
The only solution of the equation x^2 + bx + 16 = 0 is x = 4. What is the value of b?
jeka94

Answer:

yes beacajdkdnjdhdhds

Step-by-step explanation:

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8 0
3 years ago
Solve the system of equations using the addition method 2a+3b=-1 ; 3a+5b=-2
Alexeev081 [22]

Answer:

Then, a=-1 and b=-1

Step-by-step explanation:

We need to solve the following system of equations using the adition method:

2a+3b=-1       (i)

3a+5b=-2      (ii)

First, we multiply the equation (i) by -3 and the equation (ii) by 2, so we get:

-6a-9b=3

6a+10b=-4

Adding the two equations we have:

-6a-9b=3

6a+10b=-4

--------------------------

 0  + b = -1

Then b=-1. Now, let's substitute the value of b into equation (i):

2a+3b=-1

2a + 3(-1) = -1

2a -3 = -1

2a = 2

a = 1

Then, a=-1 and b=-1

3 0
4 years ago
Read 2 more answers
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