Question

81p² + 5 = 41 how do I solve by square roots​

Answer 1

Answer:

p = ± $\frac{2}{3}$

Step-by-step explanation:

Given

81p² + 5 = 41 ( subtract 5 from both sides )

81p² = 36 ( divide both sides by 81 )

p² = $\frac{36}{81}$ ( take the square root of both sides )

p = ± $\sqrt{\frac{36}{81} }$

   = ± $\frac{\sqrt{36} }{\sqrt{81} }$ = ± $\frac{6}{9}$ = ± $\frac{2}{3}$