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3 years ago

Point M is will be plotted between L and N on the number line.

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

5 0

The answer should be 19

erica [24]3 years ago

3 0

Answer:

The answer is 19

Step-by-step explanation:

I'm pretty sure the answer is 19

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A CD usually sells for $18.00. If the CD is 10% off, and sales tax is 7%, what is the total price of the CD, including tax?

yawa3891 [41]

Answer:

Step-by-step explanation:

7 0

3 years ago

If c is between a and b then Ac= CB

rodikova [14]

It only works if C is the midpoint of AB

5 0

4 years ago

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

joes family has compleated 60% of a road trip. if they have traveld 30 miles, how far is the full road trip?

Tems11 [23]

The full road trip is 50 miles.

Step-by-step explanation:

Given,

Distance traveled by Joe's family = 30 miles

This represents 60% of the total distance to be traveled.

Let,

x be the total distance.

60% of x = 30

$\frac{60}{100}*x=30\\0.6x=30$

Dividing both sides by 0.6

$\frac{0.6x}{0.6}=\frac{30}{0.6}\\x=50\ miles$

The full road trip is 50 miles.

Keywords: percentage, division

Learn more about percentages at:

#LearnwithBrainly

4 0

3 years ago

What is the square root of 72/25x4

Afina-wow [57]

Answer:

1.35764501988

Step-by-step explanation:

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3 years ago

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