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Elena L [17]
3 years ago
6

6. The heights of men selected from a particular population have a normal distribution with mean 68 inches and standard deviatio

n 4 inches. a. Find the percentage of men in the population who are taller than 72 inches. b. Find the percentage of men who are between 64 and 74 inches tall. c. Suppose 25% of men in this population are taller than Ralph. How tall is Ralph
Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

a) the proportion is 0.159 (15.9%)

b) the proportion is 0.524 (52.4%)

c) Ralph is 70.958 inches tall

Step-by-step explanation:

defining our random variable X= heights of men , then we can define the standard random variable Z as

Z= (X- μ)/σ , where  μ is the population's mean and σ is the corresponding standard deviation of X

then for X=72

Z= (X- μ)/σ

Z= (72-68)/4 = 1

a) P(X> 72) = P(Z> 1) = 1-0.841 = 0.159 (using standard normal distribution tables)

b) for X=64 and X=74

Z₁= (64 -68)/4 = -1

Z₂= (74-68)/4 = 1.5

then

P(68<X< 74) = P(-1<Z <1.5) 0 = P(Z<1.5) - P(Z<-1) =  0.933- 0.159 =0.774

c) Z₃ = 0.933 - 0.774*0.25 = 0.7395

thus

Z₃= (X₃- μ)/σ →X₃ =μ+ Z₃*σ = 68 + 0.7395*4  = 70.958 inches

therefore Ralph is 70.958 inches tall

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$7.85

Step-by-step explanation:

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23.98+7.40=31.38

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A printing press can print 224 newspapers in 8 minutes. What is the unit rate
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Divide  224 by 8 and you will get 28.

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Sanjay read 56 pages of his book this weekend.This is 35% of the pages in the book.How many pages are in Sanjays book?
Maurinko [17]
1. 56 : 35 = 1.6
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What is the solution to 5a-15+9a=3a+29
pogonyaev

5a-15+9a=3a+29

We simplify the equation to the form, which is simple to understand

5a-15+9a=3a+29

We move all terms containing a to the left and all other terms to the right.

+5a+9a-3a=+29+15

We simplify left and right side of the equation.

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3 0
3 years ago
Read 2 more answers
Write an equation of the line shown. Then use the equation to find the value of x when y=112
PtichkaEL [24]

Answer:

y = 8x + 16

x = 12

Step-by-step explanation:

Given two points on the line (0, 16) and (3, 40), an equation for the line can be written using the slope-intercept line equation which takes the format y = mx + b.

Where,

m = slope = \frac{y_2 - y_1}{x_2 - x_1}

b = y-intercept or the point at which the line cuts the y-axis.

Let's find slope (m) using the slope formula:

Let,

(0, 16) = (x_1, y_1)

(3, 40) = (x_2, y_2)

slope (m) = \frac{40 - 16}{3 - 0}

slope (m) = \frac{24}{3}

slope (m) = 8

Find b. Substitute the values of x = 0, y = 16, and m = 8 in the slope-intercept formula to find b.

y = mx + b

16 = 8(0) + b

16 = 0 + b

16 = b

b = 16

Plug in the values of m and b into the slope-intercept formula to get the equation of the line.

y = mx + b

y = 8x + 16

Let's use the equation to find x when y = 112.

y = 8x + 16

Substitute y = 112 in the equation

112 = 8x + 16

112 - 16 = 8x

96 = 8x

Divide both sides by 8

12 = x

x = 12

8 0
3 years ago
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