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3 years ago

Question 1 of 10

Mathematics

1 answer:

allsm [11]3 years ago

3 0

$\frac{f}{g} = \frac{ \sqrt[3]{2x} }{2x + 1}$

<h3>Set the denominator not equal to zero.</h3>

<h3>Letter A is your answer.</h3>

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Which of these tables represents a linear function?

Komok [63]

Answer:

The second one. it's the only one that has a pattern for both sides. for every x value that goes up, the y-values goes down one. that function has a slope of -1

Step-by-step explanation:

I hope this helps :)

4 0

3 years ago

Find the interquartile range for the data set 10,3,8,9,12,,13.

cluponka [151]

I think it is 8 but im not sure(sorry if its wrong)

7 0

4 years ago

Which are the solutions of x2 = –7x – 8?

Yanka [14]

You can start by rewriting the equation so that the right side equals zero. Add $-7x$ and $8$ to both sides.

$x^2+7x+8=0$

You can now use the quadratic equation (below), where $a=1, b=7,$ and $c=8$ , to find solutions. Plug in these values for $a, b,$ and $c$ into the equation and simplify.

$\frac{-b \pm \sqrt{b^2-4(ac)}} {2a}$
$\frac{-7 \pm \sqrt{7^2-4(1 \times 8)}} {2 \times 1}$
$\frac{-7 \pm \sqrt{49-32}} {2}$
$\frac{-7 \pm \sqrt{17}} {2}$

The final answer is the combination of both solutions.
$x=\frac{-7}{2} \pm \frac{\sqrt{17}} {2} \approx -3.5 \pm 2.06.$

Or approximately...
$x=(-3.5-2.06) \approx -5.56, (-3.5+2.06) \approx-1.44$

8 0

3 years ago

Read 2 more answers

Solve for the possible value or values of v. SELECT ALL THAT APPLY. *

OLEGan [10]

Answer:

No Solution

Step-by-step explanation:

It does not make sense to have two different variables on the same equation.

7 0

4 years ago

HELP MEE I HAVE TO TURN IT IN TOMORROW

schepotkina [342]

The answer would be 80

7 0

3 years ago