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Aliun [14]
3 years ago
10

Here are the first five terms of an arithmetic sequence. 2 6 10 14 18 Is 86 a term in the sequence? You must give a reason for y

our answer. ANSWEER NOOOWWW PLSSS
Mathematics
2 answers:
AnnyKZ [126]3 years ago
5 0

Answer:

86 is a term in the sequence

Step-by-step explanation:

2; 6; 10; 14; 18;.....

T1=1*4-2=2

T2=2*4-2=6

T3=3*4-2=10

T4=4*4-2=14

T5=5*4-2=18

......................

Tn=n*4-2

n*4-2=86

n*4=88

n=88/4

n=22

86 is T22  in  the sequence.

bazaltina [42]3 years ago
5 0
Yes, 86 is a term in the sequence because the sequence is adding by 4. If your add 4 you will eventually get to 86
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A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape....
frosja888 [35]

Answer:

About 41.5%

Step-by-step explanation:

<em>Given:</em>

<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.</em>

<em>To Find:</em>

<em>What is the probability that both grapes are red?</em>

<em>Answer choices:</em>

<em>about 39.7%</em>

<em>about 41.5%</em>

<em>about 42.5%</em>

<em>about 44.5%</em>

<em>Solution:</em>

<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .</em>

<em>As the red grapes are 15..</em>

<em>Thus,</em>

<em>The probability of choosing a red grape the first time is 15/23.</em>

<em>Because out of the total 23 grapes only 15 were red grape.</em>

<em>The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>

<em>Hence, the probability of choosing or eating two red grapes will be :</em>

<em>15/23×14/22</em>

<em>=105/253</em>

<em>=0.415</em>

<em>= 41.5%</em>

<em>Therefore, the probability that both grapes are red is about 41.5%</em>

5 0
2 years ago
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Korvikt [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Break the numbers 0-9 into 3 groups. Each group needs to equal the same number when added! Write out the groupsand the sum of ea
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we must do the following:

0

1

2

3

4

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6

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also:

\begin{gathered} 8+4+3=15 \\  \end{gathered}

the groups are:

(9,0,1,5); (7,6,2); (8,4,3)

8 0
11 months ago
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