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Oksana_A [137]
3 years ago
15

Evaluate: 100−20.2×4.5. i need this for imagen math

Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

359.1

Step-by-step explanation:

100 - 20.2 is 79.8

79.8 x 4.5 is 359.1

therefore it is 359.1

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goldenfox [79]
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6 0
3 years ago
What is 850 in scientific notation?
jonny [76]

Answer:

it is 8.5 x 10^2 because when you times the 10 twice and then multiply it with 8.5 and the decimal moves

4 0
3 years ago
(5,1); m=2 write an equation of the line
gtnhenbr [62]
Hey there! :) 

To find an equation of a line that passes through (5, 1) and has a slope of 2, we'll need to plug our known variables into the slope-intercept equation.

Slope-intercept equation : y = mx + b ; where m=slope, b=y-intercept

Since we're already given the slope, all we really need to do is find the y-intercept.

We can do this by plugging our known values into the slope-intercept equation.

y = mx + b

Since we're trying to find "b," we need to plug in "y, m, x" into our formula.

(1) = (2)(5) + b

Simplify.

1 = 10 + b

Subtract 10 from both sides.

1 - 10 = b

Simplify.

-9 = b

So, our y-intercept is 9! 

Now, we can very simply plug our known values into slope-intercept form.

y = mx + b

y = 2x - 9 → final answer

~Hope I helped!~
3 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
Write three expressions that have the same value as 745 ÷ 30.
nataly862011 [7]

Answer:

(700+40+5)/30

10(745/3)

30x=745

6 0
3 years ago
Read 2 more answers
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