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amm1812
4 years ago
7

7. Evaluate 4P2 O 22 O 12 O 14 5

Mathematics
1 answer:
Reika [66]4 years ago
5 0

Answer:

<h2>12</h2>

Step-by-step explanation:

To evaluate 4P2, we will use the permutation formula as shown;

nPr = \frac{n!}{(n-r)!}

4P2 = \frac{4!}{(4-2!}

= \frac{4!}{2!} \\= \frac{4*3*2!}{2!}\\ = 4*3\\= 12

4P2 = 12

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Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

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we will look at the table and count all the elements that are greater than 9

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The probability for event A will be

\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}

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