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NikAS [45]
4 years ago
10

Consider an experiment where we ask what type of car – either domestic (e.g., Chevrolet, Ford, Chrysler, etc.), foreign built ab

road (e.g. a Toyota built in Japan) or foreign built in the U.S. (e.g., a Toyota built in Kentucky) – and the style (sedan, hatchback, truck or SUV) of the automobiles driven by 20 different people. How many outcomes are in the sample space?
Mathematics
1 answer:
Nostrana [21]4 years ago
7 0

Answer:

12^{20} outcomes for this sample space (under some considerations)

Step-by-step explanation:

Let's define the multiplication principle.

If a first part of an experiment can happen in n1 ways, a second part of an experiment can happen in n2 ways , . . . , a i - part of an experiment can happen in ni ways, then the total outcomes for the all the experiment are

(n1) x (n2) x ... x (ni)

In this exercise n1 = domestic

n1 is the total classes for domestic category

(Let's suppose n1 = 3 because of Chevrolet, Ford and Chrysler)

n2 = 1 (Also supposing we only have ''a Toyota built in Japan'' category for n2)

n3 = 1 (Also supposing we only have ''A Toyota built in Kentucky'' category for n3)

n4 = 4 (Also supposing we only have ''sedan,hatchback, truck or SUV'' category for n4

The possible outcomes for one person in the experiment are

(Domestic).(ForeignBuiltAbrod).(ForeignBuiltInTheU.S).(Style)

Where what it is brackets are the possible categories for that classification.

n1.n2.n3.n4=3.1.1.4=12

We have 20 different people then 12^{20} are the possible outcomes sample space

In the sample space there are 12^{20} outcomes if we consider that we have 3 types of domestic car, 1 type of foreign car built abroad,1 type of foreign car built in the U.S and 4 differents styles for this 20 different people.

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If you have 14 feet of fencing, what are the areas of the different rectangles you could enclose with the fencing? Consider only
disa [49]

Answer:

Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²

Step-by-step explanation:

Feets of fencing = 14

Perimeter = 14

Let x = Length y = width

Perimeter = 2(x + y)

For x = 1

2(1 + y) = 14

1 + y = 7

y =6

Area of rectangle ; x *y = 1 * 6 = 6 ft²

For x = 2

2(2 + y) = 14

2 + y = 7

y = 5

Area of rectangle ; x *y = 2 * 5 = 10 ft²

For x = 3

2(3 + y) = 14

3 + y = 7

y =4

Area of rectangle ; x *y = 3 * 4 = 12 ft²

For x = 4

2(1 + y) = 14

4 + y = 7

y = 3

Area of rectangle ; x *y = 4 * 3 =12 ft²

Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²

8 0
3 years ago
What is the sum of the arithmetic sequence 153, 139, 125, …, if there are 22 terms?
Tamiku [17]

a_1=153\\a_2=139\\a_3=125\\\vdots\\\\d=a_2-a_1\to d=139-153=-14

The formula of the sum of the arithmetic sequence:

S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n

We have:

a_1=153\\d=-14\\n=22

substitute

S_{22}=\dfrac{2\cdot153+(22-1)\cdot(-14)}{2}\cdot22=(306+21\cdot(-14))\cdot11=132

4 0
4 years ago
Can you guys help me out
Margarita [4]

Answer:60

Step-by-step explanation:

The exact answer is 58 but then i rounded it to 60.

6 0
3 years ago
Please help! Brainliest:)
Nataliya [291]

Answer:

㏑(\frac{b7}{9})

solution

log10 (\frac{b7}{9 }  = \frac{7log 10 (b)}{9}

steps \frac{log10(b7)}{9}

simplify log 10(b7) : 7log10 (b)

= \frac{7log10(b)}{9}

8 0
3 years ago
The average of group of 13 boys is 13. When two more boyss joined the group, the average age rose by 2 years .the sum of ages of
ollegr [7]

Answer:

56 years

Step-by-step explanation:

we know that

1) The average of group of 13 boys is 13 years

so

Remember that

The average is the sum of the ages divided by the number of boys

The sum of the ages is equal to the average multiplied by the number of boys

The number of boys is 13

The average is 13

The sum of the ages is ----> 13*13=169

2) When two more boys joined the group, the average age rose by 2 years

so

Now the number of boys is 13+2=15

The average is 13+2=15

The sum of the ages is -----> 15*15=225

To find out the sum of ages of two new boys, subtract the original sum of the ages from the new sum of the ages

225-169=56 years

5 0
4 years ago
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