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ELEN [110]
3 years ago
6

HELP ON AREA PLZZZZ HELP

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0

Answer:

70cm

Step-by-step explanation:

Area of triangle:              (5.8x4)/2=11.6

Area of big rectangle:     8x5.8=46.4

Area of small rectangle:  2.4x5=12

12+46.4+11.6=70

Inessa05 [86]3 years ago
4 0
70cm have a good day :)
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What is this answer -1/2+3/4=
Over [174]

Answer:

1/4

Step-by-step explanation:

-1/2 (2/2) -> -2/4

-2/4 + 3/4 = 1/4

7 0
3 years ago
The Snow Sports Club from Sierra High School is boarding the tram at Heavenly Valley to ride up to the top of the mountain. The
hoa [83]
17 people and 9 snowboards.
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3 years ago
Read 2 more answers
Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither
Dahasolnce [82]

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This  does not work

We can stop now.  (-2,6) cannot be a solution

7 0
3 years ago
The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si
Hitman42 [59]

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean =\mu = 600 hours

Standard deviation =\sigma = 100 hours

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula:Z= \frac{x-\mu}{\sigma}

At x = 600

Z= \frac{600-600}{100}

Z=0

P(X

At x = 700

Z= \frac{700-600}{100}

Z=1

P(X

P(600

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

8 0
3 years ago
Better picture!! Please help me ASAP!! Desperate
Crazy boy [7]
The length of the picture would  be 10 inches. If the frame needs to be 34, that means 7+7 for the width and 10+10 for the length. 
4 0
3 years ago
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