Answer:
D) the carbon with the low-energy phosphate on it in 1,3 BPG is labeled.
Explanation:
Glycolysis has 2 phase (1) preparatory phase (2) pay-off phase.
<u>(1) Preparatory phase</u>
During preparatory phase glucose is converted into fructose-1,6-bisphosphate. Till this time the carbon numbering remains the same i.e. if we will label carbon at 6th position of glucose, its position will remian the same in fructose-1,6-bisphosphate that means the labeled carbon will still remain at 6th position.
When fructose-1,6-bisphosphate is further catalyzed with the help of enzyme aldolase it is cleaved into two 3 carbon intermediates which are glyceraldehyde 3-phosphate (GAP) and dihyroxyacetone phosphate (DHAP). In this conversion, the first three carbons of fructose-1,6-bisphosphate become carbons of DHAP while the last three carbons of fructose-1,6-bisphosphate will become carbons of GAP. It simply means that GAP will acquire the last carbon of fructose-1,6-bisphosphate which is labeled. Now the last carbon of GAP which has phosphate will be labeled.
<u>(2) Pay-off phase</u>
During this phase, GAP is dehydrogenated into 1,3-bisphosphoglycerate (BPG) with the help of enzyme glyceraldehyde 3-phosphate dehydrogenase. This oxidation is coupled to phosphorylation of C1 of GAP and this is the reason why 1,3-bisphosphoglycerate has phosphates at 2 positions i.e. at position 1 in which phosphate is newly added and position 3rd which already had labeled carbon.
It is pertinent to mention here that<u> BPG has a mixed anhydride and the bond at C1 is a very high energy bond.</u> In the next step, this high energy bond is hydrolyzed into a carboxylic acid with the help of enzyme phosphoglycerate kinase and the final product is 3-phosphoglycerate. Hence, the carbon with low energy phosphate i.e. the carbon at 3rd position remains labeled.
Answer: C. The volume of the sound
Explanation:
<span>A carbon - 12 atom and a
regular carbon atom would have the same number of protons which is 6. So a
carbon - 12 atom would have 6 protons. Both, however, would differ in the
number of neutrons. Carbon - 12 atom has 6 neutrons. To determine the mass
defect of a carbon - 12 atom, we have to add the total mass of protons and the
total mass of neutrons and subtract the known mass of a carbon - 12 atom. That
would be like this.<span>
6
(1.00728 amu) + 6 (1.00866 amu) = x
<span>6.04368
amu<span> + 6.05196 amu = x</span></span>
12.09564
amu = x
Then
subtract it with 12 amu to get the defect mass
12.09564
amu - 12.00000 amu = y
0.09564
amu = y
<span>So the
defect mass would be 0.09564 amu.</span></span></span>
I think the mass the mass was less than the original because a gas was released into the atmosphere. The mass in a chemical reaction is constant in a closed system according to conservation of mass law. However, if a chemical reaction is completed in an open system, mas changes may occur. In our case i think the change in mass was due to the release of hydrogen gas from the reaction to the atmosphere.
Answer:
B) flat trigonal
Explanation:
All the Hydrogen atoms are arranged symmetrically around the Nitrogen atom which forms the base, and the two nonbonding electrons form the tip
