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stealth61 [152]
3 years ago
15

Which of the following statements is true about natural gas? It can be used directly in homes. It does not pollute the atmospher

e. It is produced with the help of waterfalls. It can be transported safely with no risk of leaks.
Chemistry
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

It can be used directly in homes

Explanation:

The natural gas is one of the fossil fuels that is used on a large scale. It can be used directly in homes, as there are lot of things that have been made to run on natural gas, be it for cooking or heating. Even though this fossil fuel doesn't contribute as much to the pollution of the atmosphere as the oil and the coal, still manages to have part in it. The majority of the pollution of the natural gas comes while it is transported. Through the transportation very often there's leaking of the natural gas. As it leaks, the natural gas releases lot of methane into the atmosphere, and the methane is a more effective greenhouse gas even than the CO2, though only on the short term.

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D = m / V

D = 8.0 g  / 25 cm³

D = 0.32 g/cm³

Answer A
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Dima020 [189]
Mole ratio for the reaction is 1:1
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When iodobenzene codistills with water at 760 toor, the boiling point of the mixture is 98.5. the vapor pressure of water is?
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Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and
blondinia [14]

Answer:

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Explanation:

From the information given:

The mass of the elements are:

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To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon

For Hydrogen:

=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen

For Oxygen:

=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon

For Hydrogen:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen

For Oxygen:

\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen

Thus, the empirical formula is HCO₂

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3 years ago
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75km/hr

A car traveling with constant speed travels 150km in 7200 s. What is the speed of the car
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