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stealth61 [152]
4 years ago
15

Which of the following statements is true about natural gas? It can be used directly in homes. It does not pollute the atmospher

e. It is produced with the help of waterfalls. It can be transported safely with no risk of leaks.
Chemistry
1 answer:
yKpoI14uk [10]4 years ago
3 0

Answer:

It can be used directly in homes

Explanation:

The natural gas is one of the fossil fuels that is used on a large scale. It can be used directly in homes, as there are lot of things that have been made to run on natural gas, be it for cooking or heating. Even though this fossil fuel doesn't contribute as much to the pollution of the atmosphere as the oil and the coal, still manages to have part in it. The majority of the pollution of the natural gas comes while it is transported. Through the transportation very often there's leaking of the natural gas. As it leaks, the natural gas releases lot of methane into the atmosphere, and the methane is a more effective greenhouse gas even than the CO2, though only on the short term.

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In the first 15.0 s of the reaction, 1.9×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.480 L . What is the
N76 [4]

The question is incomplete, here is the complete question:

Consider the following reaction:  2N_2O(g)\rightarrow 2N_2(g)+O_2(g)

In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?

<u>Answer:</u> The average rate of appearance of oxygen gas is 2.64\times 10^{-3}M/s

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 1.9\times 10^{-2}moles

Volume of solution = 0.480 L

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

So, \text{Molarity of }O_2=\frac{1.9\times 10^{-2}mol}{0.480L}=0.0396M

The given chemical reaction follows:

2N_2O(g)\rightarrow 2N_2(g)+O_2(g)

The average rate of the reaction for appearance of O_2 is given as:

\text{Average rate of appearance of }O_2=\frac{\Delta [O_2]}{\Delta t}

Or,

\text{Average rate of appearance of }O_2=\frac{C_2-C_1}{t_2-t_1}

where,

C_2 = final concentration of oxygen gas = 0.0396 M

C_1 = initial concentration of oxygen gas = 0 M

t_2 = final time = 15.0 s

t_1 = initial time = 0 s

Putting values in above equation, we get:

\text{Average rate of appearance of }O_2=\frac{0.0396-0}{15-0}\\\\\text{Average rate of appearance of }O_2=2.64\times 10^{-3}M/s

Hence, the average rate of appearance of oxygen gas is 2.64\times 10^{-3}M/s

8 0
4 years ago
Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.
algol13

Answer : The value of \Delta G_{rxn} is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.1)^3}{(1.4)^2}

Q=3.375

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -28.0 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)

\Delta G_{rxn}=-24.9kJ/mol

Therefore, the value of \Delta G_{rxn} is -24.9 kJ/mol

5 0
3 years ago
Please help! Thanks
trapecia [35]

Th actual yield of the reaction is 24.86 g

We'll begin by calculating the theoretical yield of the reaction.

2Na + Cl₂ → 2NaCl

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced = 2 × 58.5 = 117 g

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore,

11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.

Thus, the theoretical yield of NaCl is 29.25 g.

Finally, we shall determine the actual yield of NaCl.

  • Percentage yield = 85%
  • Theoretical yield = 29.25 g
  • Actual yield =?

Actual yield = Percent yield × Theoretical yield

Actual yield = 85% × 29.25

Actual yield = 0.85 × 29.25 g

Actual yield = 24.86 g

Learn more about stoichiometry: brainly.com/question/25899385

7 0
3 years ago
What three ways a bicyclist can change velocity?
madam [21]

Answer:

There are three ways an object can accelerate

Explanation:

a change in velocity, a change in direction, or a change in both velocity and direction.

3 0
4 years ago
Which property can be used to tell gold and pyrite apart?
zubka84 [21]

Answer:

D. Malleability

Explanation:

Gold is made up of the element Au and it is a metal.

Pyrite is iron sulfide and it is a non-metal.

  • They have very similar appearance to such an extent that pyrite is widely called the fool's gold.
  • To distinguish between the two, we simply explore their metallic properties.
  • Gold is malleable. Pyrite is not. It will crumble under pressure.
6 0
3 years ago
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