A 7.32 g sample of copper is contaminated with 0.81 g of zinc. Suppose an atomic mass measurement was performed on this sample.
What would be the measured atomic mass?
1 answer:
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Explanation:
The given data is as follows.
Concentration = 0.1
= 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions
=
T = = (30 + 273) K = 303 K
Formula for electric double layer thickness () is as follows.
=
where, = concentration =
Hence, putting the given values into the above equation as follows.
=
=
= m
or, =
= 1 nm (approx)
Also, it is known that =
Hence, we can conclude that addition of 0.1 of KCl in 0.1
of NaBr "
" will decrease but not significantly.
Answer:
<h2>2.60 L</h2>Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>2.60 L</h3>Hope this helps you